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3 years ago

Please Help I Don't Understand How To Do This. ASAP! I need help with questions 23 and 25

Mathematics

1 answer:

Zigmanuir [339]3 years ago

5 0

23. undefined
25. x=0
y=3
Hope This Helps!

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If you are selling bag of candy would you want ti sell the candy in ounces or pounds? Explain.

7nadin3 [17]

You would want to sell the bag of candy in ounces, unless you have way too much candy.

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3 years ago

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Which expression is equivalent to (sf)(6)

SashulF [63]

Answer:

(st)(6)= s(6) * t(6)

Step-by-step explanation:

(st)(6)

(st)(x)= s(x) * t(x) we multiply it

(st)(6)= s(6) * t(6)

Hope this helps.

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3 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

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3 years ago

A number between 10 and 20 is both a foctor of 60 and<br>a multiple of 6.<br>What is the number?

Kisachek [45]

Answer:

Step-by-step explanation:

List out factors of 60 =

1 x 60 = 60

2 x 30 = 60

3 x 20 = 60

4 x 15 = 60

5 x 12 = 60

6 x 10 = 60

1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30 and 60 are factors of 60.

List out multiples of 6 from 10 to 20.

12 and 18.

Since 12 is seen on one of the factors of 60 and a multiple of 6 between 10 and 20, the answer is 12.

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3 years ago

41.3+0.7 adding and subtracting decimals

viktelen [127]

The answer would be 42
Because the 0.3 (from the number 41.3) and 0.7 make 1 so basically it would be 41+1=42
(Sorry if wrong! Mark brainiest if right!)

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