Reduce the ratio to its lowest form. 72:8
1 answer:
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Answer:
1.60
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area =
So that,
for the inner part of the pipe,
r =
=
= 2.5 feet
Area of the inner part of the pipe =
= 3.14 x
= 19.625
Are of the inner part of the pipe is 19.63 .
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r =
= 2.6 feet
Area of the pipe =
= 3.14 x
= 21.2264
Area of the pipe is 21.23 .
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 .
We have to solve this equation:
Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:
Now we can find the roots of the quadratic polynomial as:
Then, the solutions to the equation are:
x = 0
x = 3 - √3
x = 3 + √3