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4 years ago

8

A bag contains yellow marbles and red marbles, 31 in total. The number of yellow marbles is 1 less than 3 times the number of re

d marbles. How many yellow marbles are there?

1 answer:

Ghella [55]4 years ago

8 0

There are 15 yellow marbles and 16 red marbles

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4. a. If the original lengths are multiplied by 2, what are the new coordinates? *

Lapatulllka [165]

divide

Step-by-step explanation:

But i think I know what you need to do so first count the graph like see where it is pointed at then divide and u get ur answer Again im not sure but maybe

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3 years ago

Please can someone solve this question?

kaheart [24]

4 x 4 x 4 thats all ☺

7 0

3 years ago

a copy shot prints 5,493 pages they use the pages to make 68 same size booklets about how many pages are in each booklet

Aliun [14]

Answer:

80 pages

Step-by-step explanation:

Given:

Number of pages printed = 5493

Number of booklets made = 68

Let each booklet use 'x' pages.

So, pages used by 68 booklets is given by unitary method and is equal to:

$=68\times x\\=68x$

Now, total number of pages are 5493.

Therefore, the pages used by the 68 booklets should be less than or equal to the total number of pages available. So,

$68x=5493\\\textrm{Dividing both sides by 68,we get:}\\x=\frac{5493}{68}=80.8\approx 80(\textrm{As number of pages can't be in decimal})$

Therefore, the number of pages in each booklet is 80.

3 0

3 years ago

An angle measures 44° less than the measure of its complementary angle. What is the measure of each angle?

ryzh [129]

a+b=90°

a=b+44°

b+44°+b=90°

2b+44°=90°

2b=90°-44°

2b=46°

b=23°

a=23°+44°

a=67°

8 0

3 years ago

What’s the difference quotient simplified

mihalych1998 [28]

$\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}$

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3 years ago