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2 years ago

7

Burl and Paul paint signs together on a scaffold. Compared to their weights plus the weight of the scaffold, the sum of tensions

in the supporting ropes is?

1 answer:

tatyana61 [14]2 years ago

5 0

Answer:

equal

Step-by-step explanation:

If the scaffold is not accelerating either upward or downward, the sum of upward support forces is <em>the same as</em> the sum of downward weights being supported.

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Combine likes terms to create an equivalent expression 1/7 - 3(3/7h -2/7)

Anastasy [175]

$\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7}) = \frac{7-9h}{7}$

<em><u>Solution:</u></em>

<em><u>Given expression is:</u></em>

$\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})$

We have to combine the like terms

From given expression,

$\frac{1}{7} -3(\frac{3}{7}h -\frac{2}{7})$

By distributive property,

The distributive property lets you multiply a sum by multiplying each addend separately and then add the products.

a(b + c) = ab + bc

Therefore,

Solve for brackets using distributive property

$\frac{1}{7} - (3 \times \frac{3}{7}h) + (3 \times \frac{2}{7})\\\\\frac{1}{7} - \frac{9h}{7} + \frac{6}{7}$

Add 1/7 and 6/7

$\frac{1}{7} + \frac{6}{7} -\frac{9h}{7}\\\\\frac{1+6}{7} -\frac{9h}{7}\\\\Simplify\\\\\frac{7}{7}-\frac{9h}{7}\\\\1-\frac{9h}{7}\\\\Simplify\\\\\frac{7-9h}{7}$

Thus the equivalent expression is found

5 0

2 years ago

4(c + d) -3c + 5d when c=1.5 and d= -6.2

patriot [66]

Answer:

-54.3

Step-by-step explanation:

4(1.5−6.2)−4.5−31

=(4)(−4.7)−4.5−31

=−18.8−4.5−31

=−23.3−31

=−54.3

7 0

2 years ago

What is the term of a 7-term geometric series if the first term is -11 the last term is -45,056 and the common ratio is -4

shutvik [7]

I assume you mean to ask how to find the sum of the seven terms?

You have

$a_2=ra_1$
$a_3=ra_2=r^2a_1$
$a_4=ra_3=r^3a_1$
...
$a_7=ra_6=r^6a_1$

So the sum is

$a_1+ra_1+r^2a_1+\cdots+r^6a_1=a_1(1+r+r^2+\cdots+r^6)=a_1\times\dfrac{1-r^7}{1-r}$

You know that $a_1=-11$ and $r=-4$ , so the sum is equal to

$-4\times\dfrac{1-(-4)^7}{1-(-4)}=-13108$

8 0

3 years ago

A bus drives 547.25 miles on day 1 of a trip. On day 2, he drives 327.875. How many more miles did he drive the first day than t

cupoosta [38]

I did this question in my school, What u gotta do is subtract 547.25-327.875=<span>273.150</span>

5 0

3 years ago

Find the slope of the line that passes through (4,2) and (9,1)?

pshichka [43]

Answer:

The slope of the line is $\displaystyle -\frac{1}{5}$ .

Step-by-step explanation:

We are given two coordinate points:

$(4, 2)$
$(9, 1)$

We are asked to find the slope of the line.

We can use the rise-over-run formula to solve for the slope of the line.

$\displaystyle \text{slope} = \frac{\text{rise}}{\text{run}}\\\\\text{slope} = \frac{y_2-y_1}{x_2-x_1}$

However, we firstly need to name our coordinate points.

In math, we can label our coordinates using the following label system:

$(x_1, y_1), (x_2, y_2)$

Therefore, we can also label our coordinates as such:

$x_1 = 4$
$y_1 = 2$
$x_2 = 9$
$y_2 = 1$

Now, we can supply these values into the formula and solve for our slope, or a better known variable, <em>m</em>.

$\displaystyle m = \frac{1 - 2}{9 - 4}\\\\m = \frac{-1}{5}\\\\m = -\frac{1}{5}$

Therefore, our slope is $\displaystyle -\frac{1}{5}$ .

8 0

3 years ago

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