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3 years ago

What is the value of x?

Mathematics

2 answers:

seraphim [82]3 years ago

7 0

The answer is 23 cm. Please give brainliest

lbvjy [14]3 years ago

5 0

The vaue of x is 23 cm

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A music download service charges a flat fee each month and $0.99 per download. The total cost for downloading 27 songs this mont

vagabundo [1.1K]

I believe the answer is $15.45

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4 years ago

Read 2 more answers

The measure of an angle in standard position is given. Find two positive angles and two negative angles that are coterminal with

devlian [24]

Answer:

13π/4 , 21π/4, -3π/4, -11π/4

Step-by-step explanation:

Coterminal Angles are angles which share the same initial side and terminal sides.

To find coterminal angles, simply add or subtract 360° or 2π to each angle, depending on whether the given angle is in degrees or radians.

5π/4 =(4π/4)+(π/4)

Our Angle 5π/4 is in the 3rd quadrant and exceeds π radians by (π/4) radians, or 45° angular measure.

The 2 positive co-terminal angles would be:

Adding 2π

5π/4 + 2π = 13π/4

Adding another 2π

5π/4 + 2π +2π = 21π/4

The two negative co-terminal angles would be:

Subtracting 2π

5π/4 - 2π = -3π/4

Subtracting another 2π

5π/4 - 2π -2π = -11π/4

The coterminal angles are:

13π/4 , 21π/4, -3π/4, -11π/4

6 0

3 years ago

How do you work out 2 over 1.5 + 2.45 on a calculator?

erik [133]

Answer:

You have to use parenthesis

Enter:

2 ÷ (1.5+2.45) =

Step-by-step explanation:

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3 years ago

Help...Pls . I Give Scooby Schnack. I Lub You

antoniya [11.8K]

Answer: thats easy i do that

32x-81 answer question 4 is 98x-9

Step-by-step explanation:

you only multiply the number if its has an exponite and you dont add a number with an x or a y only if it has another value

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3 years ago

How can you prove that csc^2(θ)tan^2(θ)-1=tan^2(θ)

Oxana [17]

Answer:

Make use of the fact that as long as $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ :

$\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$ .

$\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}$ .

$\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ .

Step-by-step explanation:

Assume that $\sin(\theta) \ne 0$ and $\cos(\theta) \ne 0$ .

Make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ and $\csc(\theta) = (1) / (\sin(\theta))$ to rewrite the given expression as a combination of $\sin(\theta)$ and $\cos(\theta)$ .

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}$ .

Since $\cos(\theta) \ne 0$ :

$\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

By the Pythagorean identity, $\sin^{2}(\theta) + \cos^{2}(\theta) = 1$ . Rearrange this identity to obtain:

$\sin^{2}(\theta) = 1 - \cos^{2}(\theta)$ .

Substitute this equality into the expression:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}$ .

Again, make use of the fact that $\tan(\theta) = (\sin(\theta)) / (\cos(\theta))$ to obtain the desired result:

$\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}$ .

5 0

2 years ago