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neonofarm [45]
3 years ago
8

A different map has a scale of 1:50000

Mathematics
1 answer:
Deffense [45]3 years ago
6 0

Answer:

8 Km

Step-by-step explanation:

16 x 50000 = 800,000 cm

800,000 cm = 8,000 m

8,000 m = 8 km

I hope this helps, if not sorry

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The graph of a linear relationship has a slope of -5 and passes through the point (2, -12). Write the equation of the line in sl
DerKrebs [107]
<h3>Answer:</h3>

y=-5x-2

<h3>Solution:</h3>
  • We are given the line's slope and a point that it passes through.
  • Using the given information, we can write the equation of the line in Point-Slope Form:
  • y-y_1=m(x-x_1)
  • In this formula, y₁ stands for the y-coordinate of the point, m stands for the slope of the line, and x₁ stands for the x-coordinate of the point.
  • In this case, y₁ is equal to -12, m is equal to -5, and x₁ is equal to 2.
  • Plug in the values:
  • y-(-12)=-5(x-2)
  • y+12=-5(x-2)
  • Now, convert into Slope-Intercept Form, y=mx+b:
  • y+12=-5x+10
  • y=-5x+10-12
  • y=-5x-2

Hope it helps.

Do comment if you have any query.

5 0
3 years ago
What is the variable 4t+8-5c
Svetlanka [38]

Answer: The variable is t and c.

7 0
3 years ago
Perry made $34,885 this year. If the inflation rate was 6.5 percent, how much was his salary actually worth? (purchasing power)
Allushta [10]
<h3>The salary of Perry if inflation is 6.5 % is $ 32617.475</h3>

<em><u>Solution:</u></em>

Given that,

Perry made $34,885 this year

The inflation rate was 6.5 percent

To find: Salary worth if inflation rate was 6.5 percent

From given,

Inflation rate = 6.5%

Therefore,

Worth of salary due to inflation = 100 % - 6.5 % = 93.5 %

Money earned in this year by Perry = $ 34, 885

Therefore,

Worth of Perry salary due to inflation = 34,885 x 93.5%

\text{Worth of Perry salary due to inflation }= 34885 \times \frac{93.5}{100}\\\\\text{Worth of Perry salary due to inflation }= 34885 \times 0.935\\\\\text{Worth of Perry salary due to inflation }= 32617.475

Thus the salary of Perry if inflation is 6.5 % is $ 32617.475

5 0
3 years ago
A marketing research company desires to know the mean consumption of milk per week among males over age 32. A sample of 710 male
nydimaria [60]

Answer:

(4.5, 4.7)

Step-by-step explanation:

Hi!

Lets call X to the consumption of milk per week among males over age 32. X has a normal distribution with mean μ and standard deviation σ.

X \sim N(\mu, \sigma)

When you know the population standard deviation σ of X  ,  and the sample mean is \hat X, the  variable q has distribution N(0,1):

q = \frac{\hat X - \mu}{\sigma} \sim N(0,1)

Then you have:

P(-k < q

This defines a C - level confidence interval. For each C the value of k is well known. In this case C = 0.98, then k = 2.326

Then the confidence interval is:

(4.6 - 2.326*\frac{0.8}{\sqrt{710}}, 4.6 + 2.326*\frac{0.8}{\sqrt{710}})\\ (4.5, 4.7)

5 0
4 years ago
2/3 of a class are girls. A) what is the ratio girls to boys in the class? B) what is the ratio boys to girls in the class
tekilochka [14]

a) 2:1

b) 1:2

2/3 are girls so 1/3 are boys

5 0
3 years ago
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