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Ne4ueva [31]
3 years ago
10

A method a. may have zero or more parameters b. never has parameter variables c. must have at least two parameter variables d. m

ay not have only one parameter variable
Computers and Technology
1 answer:
Lynna [10]3 years ago
5 0

Answer:

The answer is "Option a"

Explanation:

A method is a technique, that associated with both a message and an object. It includes information, behavior, and actions of an interface defining, how the object can be used, and wrong choices can be described as follows:

  • In option b, It includes parameters in the method.
  • In option c, It contains a parameter, that may be one or more.
  • In option d, It contains one parameter also.

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What subnet mask can be used to segment the 172.16.0.0 network to allow for a minimum of 6 subnets while maximizing the number o
marishachu [46]

The subnet mask can be utilized to segment the 172.16.0.0 network to qualify for a minimum of 6 subnets while maximizing the numeral of broadcasters per subnet is 255.255.224.0

<h3>What do subnet masks mean?</h3>
  • A subnet mask is a 32-bit numeral formed by setting keeper bits to all 0s and developing network times to all 1s.
  • In this way, the subnet mask divides the IP speech into the network and host addresses.
  • A subnet mask is used to separate an IP address into two pieces. One element defines the host (computer), and the different part identifies the network to which it belongs.
  • To better comprehend how IP lessons and subnet masks work, look at an IP speech and see how it's managed.

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5 0
2 years ago
An engineer has reported that a printer is no longer working and needs troubleshooting. You have been informed that there is a p
gavmur [86]

Answer:

3D Printer.

extruders are in 3D printers.

7 0
2 years ago
Allocate 100 integers and assign the resulting pointers to the elements of ip_arr. Initialize each integer value to -1.
dmitriy555 [2]

Answer:

#include <iostream>

using namespace std;

int main() {

   int *ip_arr,n;//pointer name inp_arr and integer n to store the size.

   cin>>n;//size.

   for(int  i=0;i<n;i++)

   ip_arr[i]=-1;//assigning -1 to every element.

  for(int i=0;i<n;i++)

  {

       cout<<ip_arr[i]<<" ";//printing every element.

  }

return 0;

}

output:-

100

-1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 -1  

Explanation:

I am taking input of size.You should enter 100 for 100 values which have value -1.

5 0
3 years ago
Create union floatingPoint with members float f, double d and long double x. Write a program that inputs values of type float, d
Kitty [74]

Answer:

Here the code is given as follows,

#include <stdio.h>

#include <stdlib.h>

union floatingPoint {

float floatNum;

double doubleNum;

long double longDoubleNum;

};

int main() {

union floatingPoint f;

printf("Enter data for type float: ");

scanf("%f", &f.floatNum);

printf("\nfloat %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

printf("\n\nEnter data for type double: ");

scanf("%lf", &f.doubleNum);

printf("float %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

printf("\n\nEnter data for type long double: ");

scanf("%Lf", &f.longDoubleNum);

printf("float %f ", f.floatNum);

printf("\ndouble %f ", f.doubleNum);

printf("\nlong double %Lf ", f.longDoubleNum);

printf("\n\nBreakdown in Hex");

printf("\nfloat in hex %x ", f.floatNum);

printf("\ndouble in hex %x ", f.doubleNum);

printf("\nlong double in hex %Lx ", f.longDoubleNum);

return 0;

}

5 0
3 years ago
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