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3 years ago

What is the answer to this equation PLEASE HELP 2-9=?

Mathematics

1 answer:

Tanya [424]3 years ago

8 0

Answer:

(1)

Ad g(x) represent f(x) after horizontal translation 2 units to the left.

is the required translation.

(2)

(3) We have been given a point (1,-9); slope 2

We will use the equation:

m is the give slope.

Therefore, Option (a) is correct.

Step-by-step explanation:

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Pls help........................

stich3 [128]

Answer:

663

Step-by-step explanation:

Just divide

In this case 0 isn't between those numbers so the answer would be 5x0

6 0

2 years ago

Read 2 more answers

Heloo i really need help! any helo would he appreciated!

trapecia [35]

Answer:

The measure of angle DPA is 39°

Step-by-step explanation:

step 1

Find the value of x we know that arc AB+arc BC+arc CD+arc DA=360°

substitute the values

(5x+10)°+(x+1)°+3x°+(3x+25)°=360°

Solve for x

(12x+36)°=360°

12x=360°-36°

x=324°/12=27°

step 2 Find the measure of angle DPA

we know that The measurement of the external angle is the semi-difference of the arcs which comprises

m∠DPA=(1/2)[arc DA-arc BC]

arc DA=3(27)+25=106°

arc BC=27+1=28°

substitute the values

m∠DPA=(1/2)[106°-28°]=39°

6 0

3 years ago

Read 2 more answers

there were a total of twenty-one baseball games during the three month season, and four were played at night. If the game are eq

kicyunya [14]

If there were a total of 21 games played over 3 months, you divide 21 by 3.

Your answer is 7 games were played each month.

The information about how many games were played at night is useless. It's just thrown in there to confuse you. :)

6 0

3 years ago

Find the lowest common multiple of 28 and 210

Grace [21]

Answer:

420

Step-by-step explanation:

210 = 14×15

28 = 14×2

The LCM wil be the product of unique factors;

... LCM = 14×15×2 = 420

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=f%28x%29%20-%20%5Cfrac%7Bx%5E%7B2%7D-4%20%7D%7Bx%5E%7B4%7D%20%2Bx%5E%7B3%7D%20-4x%5E%7B2%7D-4%

Llana [10]

a) The given function is

$f(x)=\frac{x^2-4}{x^4+x^3-4x^2-4}$

The domain refers to all values of x for which the function is defined.

The function is defined for

$x^4+x^3-4x^2-4\ne0$

This implies that;

$x\ne -2.69,x\ne 1.83$

b) The vertical asymptotes are x-values that makes the function undefined.

To find the vertical asymptote, equate the denominator to zero and solve for x.

$x^4+x^3-4x^2-4=0$

This implies that;

$x= -2.69,x=1.83$

c) The roots are the x-intercepts of the graph.

To find the roots, we equate the function to zero and solve for x.

$\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

$\Rightarrow x^2-4=0$

$x^2=4$

$x=\pm \sqrt{4}$

$x=\pm2$

The roots are $x=-2,x=2$

d) The y-intercept is where the graph touches the y-axis.

To find the y-inter, we substitute;

$x=0$ into the function

$f(0)=\frac{0^2-4}{0^4+0^3-4(0)^2-4}$

$f(0)=\frac{-4}{-4}=1$

e) to find the horizontal asypmtote, we take limit to infinity

$lim_{x\to \infty}\frac{x^2-4}{x^4+x^3-4x^2-4}=0$

The horizontal asymtote is $y=0$

f) The greatest common divisor of both the numerator and the denominator is 1.

There is no common factor of the numerator and the denominator which is at least a linear factor.

Therefore the function has no holes.

g) The given function is a proper rational function.

There is no oblique asymptote.

See attachment for graph.

6 0

3 years ago