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3 years ago

What angle during the first revolution will have the same sin value as 20.5 degrees? Enter only a number.

Mathematics

1 answer:

const2013 [10]3 years ago

7 0

Answer:

159.5 degrees

Step-by-step explanation:

The supplement of an angle has the same sine value as the angle.

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Three consecutive even numbers have a sum where one half of the sum is between 84 and 96

mamaluj [8]

86 *2 = 172

172/3 = 57.33

54 + 56 +58 =168

168/2 =84

56 + 58 +60 = 174

174/2 =87

58 +60 +62 = 180

180/2 = 90

60 +62 +64 = 186

186/2 = 93

62 +64+66 = 192

192/2 = 96

there are 3 sets of numbers that fall between 84 & 96

1 set equals 84 and 1 set equals 96

so if you are counting those there are 5 sets

6 0

2 years ago

Simplify 〖3m〗^8 n^3÷(〖3m〗^8 n^3 )^0

vovangra [49]

$6561m^{8}n^{3}$

3 0

3 years ago

In the number 3.072 the digit 7 is in the ? place and the digit 2 is in the ? place.

notka56 [123]

Answer:

7= Hundredths

2=Thousandths

8 0

3 years ago

A line includes the points (1, 9) and (0, 5). What is it’s equation in the slope-intercept form?

scoundrel [369]

Equation is y = 4x + 5

Step-by-step explanation:

Step 1: Find the slope of the line by m = (y2 - y1)/(x2 - x1). Here y2 = 5, y1 = 9, x1 = 1 and x2 = 0

⇒ m = (5 - 9)/(0 - 1) = 4

Step 2: Find y-intercept, b. Since the line passes through (0, 5) b = 5
Step 3: Write the equation in slope-intercept form

⇒ y = 4x + 5

5 0

3 years ago

Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children

Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this problem, we have that:

$p = 0.69$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}$

$0.07\sqrt{n} = 1.2996$

$\sqrt{n} = \frac{1.2996}{0.07}$

$\sqrt{n} = 18.5658$

$(\sqrt{n})^{2} = (18.5658)^{2}$

$n = 345$

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0

3 years ago