What angle during the first revolution will have the same sin value as 20.5 degrees? Enter only a number.

Mathematics

1 answer:

const2013 [10]3 years ago

7 0

Answer:

159.5 degrees

Step-by-step explanation:

The supplement of an angle has the same sine value as the angle.

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In the accompanying diagram of right triangle ABC, the hypotenuse if AB, AC = 3, BC = 4, and AB = 5. Sin B is equal to

Trava [24]

Answer: $sin(B)=\frac{3}{5}$

Step-by-step explanation:

We are given that a triangle ABC is a Right Angled Triangle. The side AB is hypotenuse, so the angle opposite to side AB which will be angle C is a Right Angle (measures 90 degrees)

We have the side length of all 3 sides. Based on this information, we can construct a triangle with given measures. The triangle is shown in the attached image.

We have to find the value of Sin(B). Sin of an angle is defined as:

$sin(\theta)=\frac{\text{Opposite Side}}{\text{Hypotenuse}}$

The side opposite to angle B is AC with a length of 3 and hypotenuse is side AB with length 5. So Sin of angle B would be:

$sin(B)=\frac{3}{5}$

8 0

3 years ago

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm