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uysha [10]
3 years ago
8

Santiago wants to walk at least 500 miles before the end of this year. He has already walked 437 miles, and there are 36 days le

ft in the year. Which inequality can be used to find , the number of miles he should walk each day to meet his goal?

Mathematics
2 answers:
Mrrafil [7]3 years ago
7 0

Answer:

437+36x>=500

Step-by-step explanation:

This basically shows that 437 plus the x miles he will walk per day for 36 will total to more than or equal to 500

djyliett [7]3 years ago
3 0

Answer:

C 437 + 36x >_ 500

Step-by-step explanation: its because the total amount is 500 miles so its alone on one side of the equation. Then we have 437 miles + 36 days with x as a amount of how many miles per day. so first subtract 437 out off 500 then divide it by 36 which gives u X which is the answer.

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Which expression can be used to determine the length of segment AB? On a coordinate plane, triangle A B C has points (4, 3), (ne
JulijaS [17]

Answer:

StartRoot 2 squared + 6 squared EndRoot

Step-by-step explanation:

we have

A(4,3) and B(-2,1)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the given values

AB=\sqrt{(1-3)^{2}+(-2-4)^{2}}

AB=\sqrt{(-2)^{2}+(-6)^{2}}

AB=\sqrt{40}\ units

therefore

StartRoot 2 squared + 6 squared EndRoot

7 0
3 years ago
Read 2 more answers
How many hours are in 2 weeks if it is about 23.93 hours in a day?
klemol [59]
2 weeks (14 days) X 23.93 hours a day = 335.02 hours in 2 weeks 

so 14 x 23.93 = 335.02

hope I helped:)
3 0
3 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
If EF = 2x-7, FG = 4x-20, and EG = 21, find the values of x, EF, and FG.
Serggg [28]

Given -:

EF = 2X-7

FG = 4X-20

EG = 21

FIND OUT

EF =?

FG = ?

To proof

as given in the question

we have the value of EF = 2X-7 , FG = 4X-20 and EG = 21

Thus we have

EG = EF + FG

21 = 2X-7 + 4X- 20

21 = 6x - 27

48 = 6x

x = 8

Hence proved

Now put this value

EF = 2\times 8 - 7\\EF = 9

Now

FG = 4\times 8 - 20\\FG = 12

Hence proved




                   

8 0
3 years ago
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Damm [24]

Answer:

r= 12.3

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6 0
3 years ago
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