Answer:
D) would be the answer
Step-by-step explanation:
Domain is always the set of x-coordinates in the pairs and the range is always the set of y-coordinates in the pairs.
D: 7, -2, 4, -9, 0
R: 3, -2, 1, 0, 7
Put them in order from least to greatest.
D: -9, -2, 0, 4, 7
R: -2, 0, 1, 3, 7
Answer:Which is the correct path of sperm during fertilization? cervix, vagina, fallopian tube, uterus fallopian tube, uterus, cervix, vagina vagina, cervix, uterus, fallopian tube uterus, fallopian tube, vagina, cervix
answer -2
Problem 1
<h3>Answer: False</h3>
---------------------------------
Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
===============================================
Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).