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Ganezh [65]
3 years ago
9

A fireman learned a 36 foot ladder against a building.If he placed the ladder 7 feet from the base of the building,what angle is

formed between the ladder and the ground?​
Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
Answer:
The angle between the ladder and ground is 78.78°

Explanation:
It is given that the length of the ladder is 36 foot and the distance between the base and the ladder is 7 feet.

Here we can see that the hypotenuse is 36 foot and the base is 7 feet. To find the angle between the ladder and the ground we take the cos inverse of 7/36.

Let the angle between the ladder and the ground is ‘x’.

Please check the attached image, also report the answer above me for spamming and trying to receive free points as this has been an issue lately.

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8-m/n +p^2 when m=8,n=2,p=2
expeople1 [14]

8 - m/n + p^2

8 - 8/2 + 2^2

8 - 4 + 4

4 + 4

8

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

8 0
3 years ago
In the isosceles triangle ABC, we have AB=AC=4. The altitude from B meets AC at H. If AH=3(HC) then determine BC.
Inga [223]

Answer:

BC=√7

Step-by-step explanation:

AC=4

AC=AH+HC

=3HC+HC

=4HC

HC=1/4AC=1/4×4=1

AH=3HC=3×1=3

BH⊥ AC

AB=AC=4

BC=\sqrt{AB^2-AH^2} =\sqrt{4^2-3^2} =\sqrt{16-9} =\sqrt{7}

5 0
2 years ago
The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the
uranmaximum [27]

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

Given

The magnitude, M, of an earthquake is defined to be M = log StartFraction I Over S EndFraction, where I is the intensity of the earthquake (measured by the amplitude of the seismograph wave) and S is the intensity of a "standard" earthquake, which is barely detectable.

<h3>The magnitude of an earthquake</h3>

The magnitude of an earthquake is a measure of the energy it releases.

For an earthquake with 1,000 times more intense than a standard earthquake.

The equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is;

\rm M =log \dfrac{I}{S}\\\\M = log \dfrac{10s}{s}\\\\M=log 10\\\\M =1

Hence, the equation represents the magnitude of an earthquake that is 10 times more intense than a standard earthquake is \rm M = log\left ( \dfrac{10S}{S}\right ).

To know more about the magnitude of earthquakes click the link given below.

brainly.com/question/1337665

5 0
2 years ago
12. A man planted trees on both sides of
netineya [11]

Answer:

1000 trees : Can u plz give me the brainliest answer? Plz!!!!!!!!!!!!!!!

Step-by-step explanation:

5000m divided by 5m = 1000 trees

Have a nice day!!!!!! :-)

<u>KA</u>

3 0
3 years ago
Read 2 more answers
What is the following product? (2 square root 7+3 square root 6)(5 square root 2+4 square root 3)
Xelga [282]

(2\sqrt7+3\sqrt6)(5\sqrt2+4\sqrt3)\qquad\text{use distributive property}\\\\=(2\sqrt7)(5\sqrt2)+(2\sqrt7)(4\sqrt3)+(3\sqrt6)(5\sqrt2)+(3\sqrt6)(4\sqrt3)\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{12}+12\sqrt{18}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt{4\cdot3}+12\sqrt{9\cdot2}\\\\=10\sqrt{14}+8\sqrt{21}+15\sqrt4\cdot\sqrt3+12\sqrt9\cdot\sqrt2\\\\=10\sqrt{14}+8\sqrt{21}+(15)(2)\sqrt3+(12)(3)\sqrt2\\\\=\boxed{10\sqrt{14}+8\sqrt{21}+30\sqrt3+36\sqrt2}

5 0
3 years ago
Read 2 more answers
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