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Dmitriy789 [7]
3 years ago
5

If you were to plot (10, -2) and (-3, 8), what two quadrants would you be in?

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
Ten and negative 2 will be in q1 and negative 3 and 8 will be in q2
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Answer:

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Step-by-step explanation:

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3 years ago
Is anyone good with this? I need help finding the answer.
scoray [572]

Answer:

parallel:

7x - 8y = 60

perpendicular:

8x + 7y = 4

Step-by-step explanation:

original line:

-7x + 8y = 4

m = 7/8

parallel:

m = 7/8

L: 7x - 8y = k

(4, -4) -> L

28 + 32 = 60 = k

L: 7x - 8y = 60

perpendicular:

m = -8/7

L: -8x + 7y = k

(4, -4) -> L

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The length of a rectangle is 2 units more than the width. The area of the rectangle is 63 units. What is the length, in units, o
Keith_Richards [23]

Answer:

Length = 9units

Width = 7units

Step-by-step explanation:

It is said that the length is 2units more than the width

Assume that the width is x, then the length will be 2 + x

ie

Width = x

Length = 2 + x

Area of the rectangle = 63units

Area of rectangle = l * b

l - length of the rectangle

b - width of the rectangle

A = l * b

63 = (2 + x) * x

63 = ( 2 + x) x

63 = 2x + x^2

Let's rearrange it

x^2 + 2x - 63 = 0

Let's find the factor of 63

A factor that can be multiplied to give -63 and that can be added to give +2

Let's use -7 and +9

x^2 - 7x + 9x - 63 = 0

Separate with brackets

( x^2 - 7x) + ( 9x - 63) = 0

x( x - 7) + 9(x - 7) = 0

( x + 9)(x - 7) = 0

( x + 9) = 0

( x - 7) = 0

x + 9 = 0

x = -9

x - 7 = 0

x = 7

Note: the length of a rectangle can not be negative

So therefore,

x = 7

Length = 2 + x

= 2 + 7

= 9units

Width = x

= 7units

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