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4 years ago

Given the function with f(3) = 127 and f(1) = 95, determine the rate of change over the interval 1 <3 <3

Mathematics

1 answer:

Sonbull [250]4 years ago

3 0

Answer:

When we have a function f(x) = y.

The rate of change between a and b (where a < b) is:

R = (f(b) - f(a))/(b - a)

In this case:

b = 3

a = 1

f(3) = 127

f(1) = 95

R = (127 - 95)/(3 - 1) = 16

The rate of change in that interval is 16.

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If I start at 327 how do I get to finish if I have to color in numbers divisible by six

9966 [12]

Try a calculator and doing some googling of numbers divisible by six. There's a great calculator site called calculator soup! ( Yes it's really called calculator soup )

3 0

3 years ago

-4 + k/ 2 = -7 Please help guys!

yaroslaw [1]

Answer:

k=-6

Step-by-step explanation:

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3 0

4 years ago

Read 2 more answers

yra solves the equation as shown. - 3(x+2) = 9 1. - 3x - 6 = 9 2. - 3x = 15 3. x = - 5 The property Tyra used in line 1 was the:

Molodets [167]

Answer:

Distributive property says that:

$a\cdot(b+c) = a\cdot b + a\cdot c$

Addition property of equality:

if x = y then x+z = y+z

Division property of equality:

if x = y then $\frac{x}{z}=\frac{y}{z}$

As per the statement:

Given the equation: $-3(x+2)=9$

Tyra solve this equation as shown below:

$-3x -6 = 9$ [Distributive property]

$-3x = 15$ [Addition property of equality]

$x = -5$ {Division property of equality]

Therefore, the property Tyra used in line 1 was : Distributive Property.

5 0

3 years ago

Read 2 more answers

What Is 2(2x-5)=3x+x-2x ?

oksano4ka [1.4K]

Answer:

x = 5

Step-by-step explanation:

Solve for x:

2 (2 x - 5) = 3 x + x - 2 x

3 x + x - 2 x = 2 x:

2 (2 x - 5) = 2 x

Divide both sides by 2:

2 x - 5 = x

Subtract x from both sides:

(2 x - x) - 5 = x - x

2 x - x = x:

x - 5 = x - x

x - x = 0:

x - 5 = 0

Add 5 to both sides:

x + (5 - 5) = 5

5 - 5 = 0:

Answer: x = 5

7 0

3 years ago

Read 2 more answers

Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217

Soloha48 [4]

Answer:

$f(216) \approx 6.0093$

Step-by-step explanation:

Given

$\sqrt[3]{217}$

Required

Solve

Linear approximated as:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

Take:

$x = 216; \triangle x= 1$

So:

$f(x) = \sqrt[3]{x}$

Substitute 216 for x

$f(x) = \sqrt[3]{216}$

$f(x) = 6$

So, we have:

$f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)$

$f(215 + 1) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot f'(x)$

To calculate f'(x);

We have:

$f(x) = \sqrt[3]{x}$

Rewrite as:

$f(x) = x^\frac{1}{3}$

Differentiate

$f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}$

Split

$f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}$

$f'(x) = \frac{x^\frac{1}{3}}{3x}$

Substitute 216 for x

$f'(216) = \frac{216^\frac{1}{3}}{3*216}$

$f'(216) = \frac{6}{648}$

$f'(216) = \frac{3}{324}$

So:

$f(216) \approx 6 +1 \cdot f'(x)$

$f(216) \approx 6 +1 \cdot \frac{3}{324}$

$f(216) \approx 6 + \frac{3}{324}$

$f(216) \approx 6 + 0.0093$

$f(216) \approx 6.0093$

6 0

3 years ago