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Scorpion4ik [409]
3 years ago
13

9 is greater than w, and 5 is less than or equal to w

Mathematics
2 answers:
natka813 [3]3 years ago
8 0

Answer:

w = 5, 6, 7, or 8

Step-by-step explanation:

w equals one of those numbers above.

Dimas [21]3 years ago
3 0

Answer:

5≤w<9

Step-by-step explanation:

The smaller number always goes first for and statement quetions just a friendly reminder.

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Which fraction is larger: 1/4 or 2/4
melisa1 [442]
No, the answer is 1/2 (2/4). If you have a pie, cut 4 pieces, and take one piece, that is 1/4. If you cut a pie in two pieces and take one piece, you took 1/2 AND that piece you took would be bigger than the 1/4 piece.
6 0
3 years ago
Read 2 more answers
Suppose a geyser has a mean time between eruptions of 72 minutes. Let the interval of time between the eruptions be normally dis
nikitadnepr [17]

Answer:

(a) The probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is 0.3336.

(b) The probability that a random sample of 13-time intervals between eruptions has a mean longer than 82 ​minutes is 0.0582.

(c) The probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is 0.0055.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) The population mean must be more than 72​, since the probability is so low.

Step-by-step explanation:

We are given that a geyser has a mean time between eruptions of 72 minutes.

Also, the interval of time between the eruptions be normally distributed with a standard deviation of 23 minutes.

(a) Let X = <u><em>the interval of time between the eruptions</em></u>

So, X ~ N(\mu=72, \sigma^{2} =23^{2})

The z-score probability distribution for the normal distribution is given by;

                            Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

Now, the probability that a randomly selected time interval between eruptions is longer than 82 ​minutes is given by = P(X > 82 min)

       P(X > 82 min) = P( \frac{X-\mu}{\sigma} > \frac{82-72}{23} ) = P(Z > 0.43) = 1 - P(Z \leq 0.43)

                                                           = 1 - 0.6664 = <u>0.3336</u>

The above probability is calculated by looking at the value of x = 0.43 in the z table which has an area of 0.6664.

(b) Let \bar X = <u><em>sample mean time between the eruptions</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

           n = sample of time intervals = 13

Now, the probability that a random sample of 13 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P(\bar X > 82 min)

       P(\bar X > 82 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{82-72}{\frac{23}{\sqrt{13} } } ) = P(Z > 1.57) = 1 - P(Z \leq 1.57)

                                                           = 1 - 0.9418 = <u>0.0582</u>

The above probability is calculated by looking at the value of x = 1.57 in the z table which has an area of 0.9418.

(c) Let \bar X = <u><em>sample mean time between the eruptions</em></u>

The z-score probability distribution for the sample mean is given by;

                            Z  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean time = 72 minutes

           \sigma = standard deviation = 23 minutes

           n = sample of time intervals = 34

Now, the probability that a random sample of 34 time intervals between eruptions has a mean longer than 82 ​minutes is given by = P(\bar X > 82 min)

       P(\bar X > 82 min) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{82-72}{\frac{23}{\sqrt{34} } } ) = P(Z > 2.54) = 1 - P(Z \leq 2.54)

                                                           = 1 - 0.9945 = <u>0.0055</u>

The above probability is calculated by looking at the value of x = 2.54 in the z table which has an area of 0.9945.

(d) Due to an increase in the sample size, the probability that the sample mean of the time between eruptions is greater than 82 minutes decreases because the variability in the sample mean decreases as the sample size increases.

(e) If a random sample of 34-time intervals between eruptions has a mean longer than 82 ​minutes, then we conclude that the population mean must be more than 72​, since the probability is so low.

6 0
3 years ago
Graph the set of points. which model is most appropriate for the set (-6 4) (-4 0) (-3 -2) (-1 -7)
Free_Kalibri [48]

Answer:

The linear regression model is y=-2.19x-8.92.

Step-by-step explanation:

The given data points are (-6 4) (-4 0) (-3 -2) (-1 -7). Plot these points on a coordinate plane.

From the graph it is clear that the point are in the form of a straight line, so we need to use the linear regression model.

The general linear regression model is

y=ax+b

Using technology we get

a=-2.1923076923\approx -2.19

b=-8.9230769231\approx -8.92

Put a=-2.19 and b=-8.92 in  the above equation.

y=-2.19x-8.92

Therefore the linear regression model is y=-2.19x-8.92.

8 0
3 years ago
A wall is 4 m by 3 m. Which is the correct unit of measurement to use when figuring out how much paint to buy to cover the wall?
7nadin3 [17]
The answer would be b
6 0
3 years ago
(02.02 HC)
Dima020 [189]
Hey there!

It seems as if you found the answer to your problem?  If you need any help though, just let me know!

Let me know if you'd like me to explain how I got this answer!
3 0
3 years ago
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