Answer:
6.39
Step-by-step explanation:
divide the total cost by the total amount of the item for the unit price:
38.34/6=6.39
A is the correct answer. The correct answer is A
Answer:
The probability is ![P( p < 0.9207) = 0.0012556](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%200.0012556)
Step-by-step explanation:
From the question we are told
The population proportion is ![p = 0.96](https://tex.z-dn.net/?f=p%20%3D%200.96)
The sample size is ![n = 227](https://tex.z-dn.net/?f=n%20%20%3D%20%20227)
The number of graduate who had job is k = 209
Generally given that the sample size is large enough (i.e n > 30) then the mean of this sampling distribution is
![\mu_x = p = 0.96](https://tex.z-dn.net/?f=%5Cmu_x%20%3D%20p%20%3D%200.96)
Generally the standard deviation of this sampling distribution is
![\sigma = \sqrt{\frac{p (1 - p )}{n} }](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%5Csqrt%7B%5Cfrac%7Bp%20%281%20-%20p%20%29%7D%7Bn%7D%20%7D)
=> ![\sigma = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%20%5Csqrt%7B%5Cfrac%7B0.96%20%281%20-%200.96%20%29%7D%7B227%7D%20%7D)
=> ![\sigma = 0.0130](https://tex.z-dn.net/?f=%5Csigma%20%20%3D%200.0130)
Generally the sample proportion is mathematically represented as
![\^ p = \frac{k}{n}](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%20%5Cfrac%7Bk%7D%7Bn%7D)
=> ![\^ p = \frac{209}{227}](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%20%5Cfrac%7B209%7D%7B227%7D)
=> ![\^ p = 0.9207](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%200.9207)
Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as
![P( p < 0.9207) = P( \frac{\^ p - p }{\sigma } < \frac{0.9207 - 0.96}{0.0130 } )](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%20P%28%20%5Cfrac%7B%5C%5E%20p%20-%20p%20%7D%7B%5Csigma%20%7D%20%3C%20%20%5Cfrac%7B0.9207%20-%200.96%7D%7B0.0130%20%7D%20%20%29)
![P( p < 0.9207) = P(Z< -3.022 )](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%20P%28Z%3C%20-3.022%20%29)
From the z table the area under the normal curve to the left corresponding to -3.022 is
![P(Z< -3.022 ) = 0.0012556](https://tex.z-dn.net/?f=P%28Z%3C%20-3.022%20%29%20%3D%200.0012556)
=> ![P( p < 0.9207) = 0.0012556](https://tex.z-dn.net/?f=P%28%20p%20%3C%20%200.9207%29%20%3D%200.0012556)
5/20 in simplest form
1) 5/20 can be divided by 5
5 ÷ 5 = 1
20 ÷ 5 = 4
It cant be divided any more
5/20 in simplest form is 1/4