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allsm [11]
3 years ago
9

In bioligy class cher is viewing cells with a microscope. cell h measures 8.76x10^-3 microns in diameter and cell v measures 2.1

9x10^-5 microns in diameter. how many tines larger is the bigger cell than the smaller cell?
Mathematics
1 answer:
3241004551 [841]3 years ago
6 0

Answer:

Larger cell 400 times  bigger cell than the smaller cell

Step-by-step explanation:

Given:

diameter of the cell h =  8.76\times10^{-3}

diameter of the cell v  =2.19 \times10^{-5}

To Find:

How many tines larger is the bigger cell than the smaller cell?

Solution:

The  cell h with diameter   8.76\times 10^{-3} is larger and the cell v with diameter 2.19 \times 10^{-5} is small. To find the number of times it is larger,  we can divide the larger cell diameter by smaller cell diameter

=>\frac{8.76\times 10^{-3}}{2.19 \times 10^{-5}}

=>\frac{8.76\times 10^ {-3} \times 10^{5}}{2.19 }

=>\frac{8.76\times 10^ {(-3+5)}}{2.19 }

=>\frac{8.76\times 10^2}{2.19 }

=>\frac{876}{2.19}

=> 400

Larger cell is the bigger cell than the smaller cell by 400 times

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