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andreev551 [17]
3 years ago
11

7-11 Show work Explain work

Mathematics
1 answer:
GREYUIT [131]3 years ago
4 0
27 = forty five to the secmventh
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How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird
NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}

Then

Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\

Note that since

F \cap R=\varnothing, Perm(F)\cap Perm(R)\ne \varnothing

But since

B \cap R \ne \varnothing, Perm(B)\cap Perm(R)= \varnothing

and

B \cap F \ne \varnothing , Perm(B)\cap Perm(F)= \varnothing

Since

|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\

where |Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}

and

|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0
2 years ago
What is the mode of the following set of data?
Katena32 [7]
2) 60 because it's the one that appear the most
8 0
3 years ago
Do we have to multiply 21.88 with 4 or what helppp
umka21 [38]
No, you divide 21.88 by 4.
6 0
3 years ago
Read 2 more answers
CALCULUS RELATED RATES: A 20 foot ladder is leaning against a wall. The base of the ladder is placed 6 feet from the bottom of t
Daniel [21]

Answer:

2.17ft/s

Step-by-step explanation:

Look at the sketch of ladder at the beginning and after 3 seconds it starts to fall,

Distance of ladder from the wall 3 seconds after ladder starts to fall                                       =  Initial distance+  Velocity× time

= 6 + 2×3

= 12ft

Use trignometry to find out the speed of the top of ladder

cosθ= 12/20

θ= 0.825 rad

tan θ= v/2

v= 2.17ft/s

                                                                     

7 0
3 years ago
Formulas A=bh/2 A=bh and I have 6in 4in 6in 10in and I have to find the area
Naddik [55]

Answer:

Lots of "ifs" here.

A=bh/2 is the formula for the area of a triangle.

A=bh is the formula for the area of a rectangle or a parallelogram.

If the 6 & 4 area the base & height of a rectangle, then (6)(4) = 24 in^2

If the 6 & 10 are the base and height of a triangle, then 1/2(6)(10) = 30 in^2

Step-by-step explanation:

6 0
3 years ago
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