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Anastaziya [24]
3 years ago
8

3x = 729 Solve for x plz help. it's urgent. Will mark brainly

Mathematics
2 answers:
DedPeter [7]3 years ago
7 0

Answer: x=243

Step-by-step explanation:

o-na [289]3 years ago
6 0
Divided 3 on both sides

X= 243

Hope this helps!
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The curve y = |x|/ 5 − x2 is called a bullet-nose curve. find an equation of the tangent line to this curve at the point (2, 2).
diamong [38]
We have the following curve:

y=\frac{\left | x \right |}{5-x^2}

So we need to find <span>an equation of the tangent line to this curve at the point (2,2). So let's find out if this point, in fact, belongs to the curve:

</span>If \ x=2 \\ \\ y=\frac{\left | 2 \right |}{5-2^2}=\frac{\left | 2 \right |}{5-4}=2. 
<span>
We also know that:

</span>\left | x \right |= \left \{ {{x \ if \ x \ \geq 0} \atop {-x \ if \ x\ \textless \ 0}} \right.<span>

Given that the point is:

</span>(2,2)\ that \ is: \\ x=2\ \textgreater \ 0

Then we will say that:

\left | x \right |=x

Therefore:

y=\frac{x}{5-x^2}

Computing the derivative:

y=\frac{x}{5-x^2} \\  \frac{dy}{dx}= \frac{(1)(5-x^2)-(-2x)x}{(5-x^2)^2}=\frac{5+x^2}{(5-x^2)^2}

So the derivative solved for x=2 is in fact the slope of the line at the point (2,2), then:

\frac{dy}{dx} |_{x=2}=\frac{5+x^2}{(5-x^2)^2}|_{x=2}=\frac{5+2^2}{(5-2^2)^2}=9 \\ \\ \therefore m=\frac{dy}{dx} |_{x=2}=9

Finally, the tangent line is:

y-y_1=m(x-x_1) \\ \therefore y-2=9(x-2) \\ \therefore \boxed{y=9x-16}

<em>This is shown in the figure below.</em><span>
</span>

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