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3 years ago

You are playing a video game called "Zombie Attack."

Mathematics

1 answer:

Volgvan3 years ago

6 0

120 + 5k = 350
120 + 5k - 120 = 350 - 120
5k = 230
5k/5 = 230/5
K = 46

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A gerbil cage,priced at $18, is discounted 20% for one week, and then this price is marked up 20%. is the price back to 20% expl

stiks02 [169]

No, it isn't!

first, the discount is 20 percent of 18 dollars, that is 18/5=3.6

this means that during the first week the prize is 18-3.6=14.4

now, the prize is marked up 20 % of 14.4! this is 2.88

so the prize later will be 14.4+2.88, that is 17.28, not 18

what is relevant here is what a number is a percent OF

6 0

3 years ago

two irregular pentagons are constructed so that every side has length of 1 unit. Does this necessarily mean that these figures a

algol [13]

Answer:

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2 years ago

242 X 38 1 9 36 9,1 96 Which digits belong in the blue boxes shown on the multiplication problem?

babymother [125]

Answer:

C. 726

Step-by-step explanation:

9196-1936=7260 and take away the 0 so your answer will be 726

4 0

2 years ago

Read 2 more answers

Please help!! I’ve been struggling for days.

Tomtit [17]

Answer:

y=-1/4x-6

Step-by-step explanation:

y intercept is -6 and slope is -1/4

point slope is y-y1=m(x-x1)

you can use and point. i am using (0,-6)

y--6=-1/4(x-0)

y+6=-1/4x

-6 -6

y=-1/4x-6

7 0

3 years ago

100 POINTS TO RIGHT AWNSER!!!!

makvit [3.9K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3000586

——————————

The answer is option D) r < 5 or r > – 1.

I'm going to graph each inequality below on a number line.

A) r > 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r>5~~or~~r>-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

The result is found just by joining those two intervals together. Actually that compound inequality only implies

r > – 1

which does not represent all real numbers.

—————

B) r > 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r>5}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\textsf{|||||}\!\!\underset{5}{\circ}\!\!\overset{*****~~~}{\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\ \mathsf{r5~~or~~r$

Numbers between – 1 and 5 (including them) are not included in the union, so you don't have all real numbers represented there either.

—————

C) r < 5 or r < – 1.

$\large\begin{array}{cl} \mathsf{r$

Numbers that are greater or equal to 5 are not in the union. So it does not represent all real numbers.

—————

D) r < 5 or r > – 1.

$\large\begin{array}{cl} \mathsf{r-1}&\qquad\mathsf{\textsf{|||}\!\!\!\underset{-1}{\circ}\!\!\!\overset{********************~~~}{\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}}\\\\\\ \mathsf{r-1}&\qquad\mathsf{\overset{~~~**************************~~~}{\textsf{|||}\!\!\!\underset{-1}{\bullet}\!\!\!\textsf{|||||}\!\!\underset{5}{\bullet}\!\!\textsf{|||}}\!\!\!\footnotesize\begin{array}{l}\blacktriangleright \end{array}\qquad \mathbb{R}} \end{array}$

Now all real numbers are included in the union. So this is the right choice.

Answer: option D) r < 5 or r > – 1.

I hope this helps. =)

6 0

3 years ago