Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?
step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3
step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15
the answer Part 1) isy=(1/3)*x+15Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line
y=(1/3)*x+15then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33
so
<span>the point does not belong to the given line
</span>
the answer Part 2) isthe point does not belong to the given line
see the attached figure
The answer would be 390+ 390 =780
Answer:
x = 10
y = 40
Step-by-step explanation:
60° + (2x + 7y)° = 180° because these two angles are supplementary
So 2x + y would be equal to 60°
60° + (2x + 7y)° = 180° subtract 60 from both sides
2x + 7y = 120 and
2x + y = 60 multiply second equation by -1 and it will be -2x -y = -60 now add it to first equation
2x + 7y -2x - y = 120 - 60 -2x will eliminate 2x
6y = 60 divide both sides by 6
x = 10
if 2x + y = 60 the we need to replace x with the value we found
2×10 + y = 60
y = 40
Answer:
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formula : l x B = 10 x 16 = 160 sq