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agasfer [191]
4 years ago
13

(K-10) divided by 2 = -7 What’s the answer for the variable k?

Mathematics
1 answer:
stira [4]4 years ago
7 0

Answer:

k = -4

Step-by-step explanation:

(k - 10)/2 = -7

First: multiply by 2 to get rid of the denominator

2(k - 10)/2 = 2(-7)

k - 10 = -14

Next: add 10 to both sides to isolate k

k - 10 + 10 = -14 + 10

k = -4

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What are the zeros of the polynomial function f(x) = x(x + 5)(x – 8)?
elena-14-01-66 [18.8K]

0,-5,8

To find the zeros, set each equation equal to 0

x=0

x+5=0

x-8=0

Then solve

x=0

x=-5

x=8

So the zeros are 0,-5, and 8

7 0
4 years ago
I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS!!!
arsen [322]

Answer:

The answers are H and A, let me know in a comment if you want me to explain it

3 0
3 years ago
Trevor and $826 on account during 2.5% annual interest for seven years.
photoshop1234 [79]

Trevor invested $ 4720

<em><u>Solution:</u></em>

Given that, Trevor earned $ 826 on account during 2.5% annual interest for seven years

We can simple interest formula

<em><u>The formula for simple interest is given as:</u></em>

\text{ Simple Interest } = \frac{p \times n \times r}{100}

Where,

"p" is the principal

"n" is the number of years

"r" is the rate of interest

Here given that,

Principal = p = ?

rate of interest = r = 2.5 %

number of years = n = 7

Simple interest earned = 826

<em><u>Substituting the values in above formula,</u></em>

826 = \frac{p \times 7 \times 2.5}{100}\\\\82600 = p \times 7 \times 2.5\\\\82600 = 17.5p\\\\p = \frac{82600}{17.5}\\\\p = 4720

Thus he invested $ 4720

7 0
3 years ago
The population of Austin, Texas, was about 494,000 at the beginning of a decade. The population increased by 3% each year. Write
matrenka [14]

Answer:

y(t) = 494 (1.03)^t

y(10) = 663,89

Step-by-step explanation:

An increase in population by 3% each year means that at the end of each year, the population is 1.03 times what it was at the start of the year

This increase in population continues for t years

Exponential growth model that represents the population y (in thousands) t years after the beginning of the decade is

y(t) = 494 (1.03)^t

Where,

y = population

t = number of years

Find y when t = 10

y(t) = 494 (1.03)^t

y(10) = 494 (1.03)^10

= 494 ( 1.3439)

= 663.8866

Approximately y(10) = 663.89

This means that after 10 years from when the population was 494,000, it increased to 663,89.

4 0
4 years ago
There are 203 apples in a basket. How many children can share these apples equally? How many apples would each child get? List a
Crazy boy [7]

There are 203 apples in a basket.

The prime factors of 203 is 1, 7, 29 and 203

7 and 29 divide 203 completely

7 children can get 29 apples equally or 29 children can get 7 apples equally.

(a) 7 or 29 or 203 children share the apples equally.

(b) 29 or 7 or 1 apple they will get

The possible numbers are 7 , 29 and 203

5 0
4 years ago
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