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Kay [80]
4 years ago
7

What is the total if you multiply 10x10?

Mathematics
2 answers:
Scilla [17]4 years ago
5 0
The answer would be 100
goblinko [34]4 years ago
4 0
The total would be 100
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What happens to a graph if the y-intercept changes from -1 to 5
svlad2 [7]

Answer:

Option (d).

Step-by-step explanation:

5 - (-1) = 6.

The graph will be translated  6 units upwards.

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The "to prove" part of the information is the _____ of the "if-then" statement. if then none of the above
Ronch [10]

<u>Answer:</u>

The correct answer option is 'then'.

<u>Step-by-step explanation:</u>

The "to prove" part of the information is the 'then' of the "if-then" statement.

For example, we have this problem:

y = 2 x - 1

If x = 3, then find the value of y.

Here in this problem, we are asked that 'if' the value of x is true then prove it by substituting in the value.

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3 years ago
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The following drawing contains two _ angels.
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We need to see a picture
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Convert to a fraction: 0.18
MatroZZZ [7]

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9/50

Step-by-step explanation:

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3 years ago
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Please help asap, brainliest,thanks, and 50 points. Thank you soooo much! &lt;3
Anuta_ua [19.1K]

Answers:

1) x^{8} y^{8}

2) y^{3} \sqrt{y}

3) 5x^{4} \sqrt{6}

4) \sqrt{7}

5) \frac{\sqrt{z}}{z}

Step-by-step explanation:

1) \sqrt{x^{16} y^{36}}

Rewriting the expression:

(x^{16} y^{36})^{\frac{1}{2}}

Multiplying the exponents:

x^{\frac{16}{2}} y^{\frac{36}{2}}

Simplifying:

x^{8} y^{8}

2) \sqrt{y^{7}}

Rewriting the expression:

\sqrt{y^{6} y}=(y^{6} y)^{\frac{1}{2}}

Multiplying the exponents:

y^{\frac{6}{2}} y^{\frac{1}{2}}

Simplifying:

y^{3} y^{\frac{1}{2}}=y^{3} \sqrt{y}

3) \sqrt{150 x^{8}}

Rewriting the expression:

\sqrt{(6)(25) x^{8}}

Since \sqrt{25}=5:

5x^{4}\sqrt{6}

4) \frac{7}{\sqrt{7}}

Multiplying numerator and denominator by \sqrt{7}:

\frac{7}{\sqrt{7}} (\frac{\sqrt{7}}{\sqrt{7}})=\frac{7}{7\sqrt{7}}

Simplifying:

\sqrt{7}

5) \frac{5z}{\sqrt{25 z^{3}}}

Rewriting the expression:

\frac{5z}{5z \sqrt{z}}

Simplifying:

\frac{1}{\sqrt{z}}

Since we do not want the square root in the denominator, we can multiply numerator and denominator by \sqrt{z}:

\frac{1}{\sqrt{z}}(\frac{\sqrt{z}}{\sqrt{z}})

Finally:

\frac{\sqrt{z}}{z}

3 0
4 years ago
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