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Gre4nikov [31]
3 years ago
9

Brianna wants to buy a digital camera for a photography class. One store offers the camera for $48 down and a payment plan of $2

1 per month. The payment plan for a second store is described by y = 14x + 76, where y is the total cost in dollars and x is the number of months. Which camera is cheaper when the camera is paid off in 12 months? Complete the explanation.
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer:

the second store

Step-by-step explain: the second store is 244 but the first store is 300..i hope this helps. 14*12+76=244 and 21*12 + 48 is 300

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I need help if you get it right I will mark you
pav-90 [236]

Answer:

%30 off is the better price

Step-by-step explanation:

firstly we know that 2 - 12 is equal to 10 so that is $10.00 there from that coupon

to find out the second value, we first devide by the total amount (%100 in this case)

<em>12 / 100 = 10.12</em>

then we multiply by the partial amount (%30)

<em>0.12 * 30 = 3.6</em>

convert that into a dollar amount and we get the total discount in dollars

<em>3.60 = $3.60</em>

AND

<em>$3.60 > $2.00</em>

<em />

hope this helps ya, take care mate :D

6 0
3 years ago
Read 2 more answers
Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( \frac{3}{2}, 0 )

7 0
3 years ago
PLEASE HELP!!!!! What is the value of x in the matrix equation below?
Brums [2.3K]

The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right]  =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Matrix equality gives,

1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2

Solving the equations together,

y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10

We can see that the equations are not consistent.

There is no solution.

3 0
3 years ago
NAMED BRAINLIEST FOR FIRST ANSWERER!!
TiliK225 [7]

Answer:

$44 hope it helps

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The relationship between V, the value of his car, in dollars, and t, the elapsed time, in years, since he
Sergio [31]

Answer:

t = -24*log(2/3)

Step-by-step explanation:

The expression is:

V = 22,500*10^(-t/12)

Replacing with V = 10,000 and isolating t, we get:

10,000 = 22,500*10^(-t/12)

10,000/22,500 = 10^(-t/12)

4/9 = 10^(-t/12)

(2/3)² = 10^(-t/12)

2*log(2/3) = -t/12

-12*2*log(2/3) = t

t = -24*log(2/3)

6 0
3 years ago
Read 2 more answers
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