Step-by-step explanation:
y2 + 4y - 5
( y + 4 )( y - 1 )
so you just need to break down the sum
Here, let the age of student be x and teacher be 4x after 28 years, the teacher is double the age of student. So the age of teacher will be 4x+28 and student will be 2(x+28)
So,
4x+28=2(x+28)
4x+28=2x+56
4x-2x=56-28
2x=28
x=14
Therefore the age of the teacher in present will be
=4x+28
=4*14+28
=84
And age of student will be:
=x+28
=14+28
=42
Hope this helps
(X,Y) 0=X and 0=Y if you plug in 0 for X and 0 for Y in Y=8X it will be 0=8(0). 8 times 0 is 0 which is the equation
