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aalyn [17]
2 years ago
5

2x - y = 0 4x - y = 0

Mathematics
2 answers:
zaharov [31]2 years ago
7 0

Answer:

x=0, y=0. (0, 0).

Step-by-step explanation:

2x-y=0

4x-y=0

----------

y=2x-0

y=2x

4x-2x=0

2x=0

x=0/2

x=0

y=2(0)=0

Delicious77 [7]2 years ago
6 0

Answer:

what's the question here ?

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\theta is in quadrant I, so \cos\theta>0.

x is in quadrant II, so \sin x>0.

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and

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as well as the definition of tangent:

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2. \cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}

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\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2

\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2

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Because x is in quadrant II, we know that \dfrac x2 is in quadrant I. Specifically, we know \dfrac\pi2, so \dfrac\pi4. In this quadrant, we have \tan\dfrac x2>0, so

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