Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer: 0.75
Step-by-step explanation:
We can do this by drawing a terminal side in a standard position and then drawing the associated triangle. We then use the Pythagoras theorem to find the missing side the hypotenuse. Then, this will give a Pythagorean Triplet of 3, 4 and 5.
We now have a triangle with the values of:
x = 4
y =3
h^2= 4^2 + 3^2
h^2 = 16 + 9
h^2 = 25
h = 5
h = 5
Tangent = opposite/adjacent
= y/x
= 3/4
= 0.75
Answer:
Any-where below 1 and above 0
Step-by-step explanation:
I had this problem in math and my teacher told me this
Answer:
18
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
here [ a, b ] = [ 1, 5 ]
f(b) = f(5) = 3 × 5² = 75
f(a) = f(1) = 3 × 1² = 3, hence
average rate of change = 
= 
= 18
Answer:
Um i think it would be
does not exist
Step-by-step explanation:
sorry if wrong im a little bad at that
