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4 years ago

Multiple choice help plz!

Mathematics

2 answers:

Nuetrik [128]4 years ago

8 0

Answer is 110 to your question//

velikii [3]4 years ago

3 0

I think the answer is 110 degrees because it is a corresponding angle to the angle above.

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To get to work, you drive for 20 minutes at 30 mph, and walk 10 more minutes at 3 mph. What was your average speed?

fiasKO [112]

Note D = r(t)
20min = 1/3 hr and 10min = 1/6 hr

(1/3hr)30mph + (1/6hr)3mph = 10.5 mi, the total distance traveled.

total distance / total time = average speed = 10.5/(1/3 + 1/6) = 10.5/(2/6 + 1/6)
10.5mi/.5hr = 21mph

Hope This Helps

3 0

4 years ago

Hospitals typically require backup generators to provide electricity in the event of a power outage. Assume that emergency backu

JulsSmile [24]

Answer:

a) There is a 10.24% probability that both generators fail during a power outage.

b) There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

Step-by-step explanation:

For each emergency backup generator, there are only two possible outcomes. Either they work correctly, or they fail. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

Assume that emergency backup generators fail 32% of the times when they are needed. So they work correctly 100-32 = 68% of the time. So $p = 0.68$

There are two generators, so $n = 2$

a. Find the probability that both generators fail during a power outage

This is $P(X = 0)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.68)^{0}.(0.32)^{2} = 0.1024$

There is a 10.24% probability that both generators fail during a power outage.

b. Find the probability of having a working generator in the event of a power outage. Is that probability high enough for the hospital? Assume the hospital needs both generators to fail less than 1% of the time when needed.

Either there are no working generators, or there is at least one working generator. The sum of the probabilities of these events is decimal 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$ . So

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1024 = 0.8976$

There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

To be high enough for the hospital, this probability should be at least of 99%.

7 0

4 years ago

Simplify and find the value of the expression if x=2 and y = 13xy (4x- 5y) +3xsquare y

maria [59]

Answer:

13 + 4(2) - 5(13) + 3

multiply the numbers

13 + 8 - 65 + 3

calculate the sum or difference

= -41

Step-by-step explanation:

3 0

3 years ago

Paula dives into a swimming pool from a diving board 2 feet above the water's surface. She descends to a depth 7 feet below the

Paha777 [63]

Answer:

Your mom

Step-by-step explanation:

5 0

3 years ago

Someone help me with all of this

Gre4nikov [31]

I’m working on the same thing in school! For number 2, what i would do is start by setting up the scatter plot by using the X and Y table and create origins to place on the graph. ( ex. (1,30) for your first one ). Also, remember to write in the laps completed and calories burned. Next, estimate a line that meets as many points as possible. ( I would use the completed scatter plot in number 3 for an example for how to draw the line ). And that’s all I can help you with :( I forgot how to do the equation part because I just started with this on Monday. Hope this helps!
-Taylor

4 0

3 years ago