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d1i1m1o1n [39]
3 years ago
9

Helps, my brain cannot process

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
7 0
Either 11 if you round down but 12 if you round up
Annette [7]3 years ago
5 0

Answer:

12

Step-by-step explanation:

You might be interested in
What is the total area of the figure? (square inches)
Radda [10]

Answer:

60

Step-by-step explanation:

TOTAL SURFACE AREA = AREA OF SQUARE+2×(AREA OF TRIANGLE)

=(6×6)+2×(1/2×6×4)

=36+24=60 square inches

I hope it helped you

7 0
2 years ago
Read 2 more answers
Moira said, "If a right triangle has one side with a length of 3 units and one side with a length
Dima020 [189]

If the two sides with length 3 and 4 are the two legs, then the missing side, i.e. the hypotenuse, is indeed 5.

But it could also be the case that 4 is the hypotenuse and 3 is one of the legs. In this case, the missing side is the other leg, so we calculate it using

\sqrt{4^2-3^2}=\sqrt{16-9}=\sqrt{7}

So, a right triangle with legs \sqrt{7} and 3 has an hypotenuse of 4.

8 0
3 years ago
What is the area of triangle pqr on the grid? a triangle pqr is shown on a grid. the vertex p is on ordered pair 7 and 6, vertex
horsena [70]

P(7,6), Q(1,6), R(4,2)

We have PQ parallel to the x axis. We'll call that the base,

b = 7 - 1 = 6

The altitude is then the y difference h = 6 - 2 = 4

The area is \frac 1 2 bh = \frac 1 2 (6)(4) = 12

Answer: 12 square units


In general we can use the shoelace formula for the area of any polygon given coordinates. We write the points like this:

(7,6), (1,6), (4,2)

(1,6), (4,2), (7,6)

The area is then half the absolute value of the sum of the cross products:

A = \frac 1 2 | 7(6)-6(1) + 1(2)-6(4) + 4(6)-2(7) | = \frac 1 2 |24| = 12


6 0
3 years ago
Read 2 more answers
6.
Rudik [331]

Answer:

  (a)  169.1 m

Step-by-step explanation:

The diagram shows you the distance (x) will be shorter than 170 m, but almost that length. The only reasonable answer choice is ...

  169.1 m

__

The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

The leg of the right triangle adjacent to the marked angle is x, and the hypotenuse is 170 m. Putting these values into the equation, you have ...

  cos(6°) = x/(170 m)

  x = (170 m)cos(6°) ≈ (170 m)(0.994522) ≈ 169.069 m

The horizontal distance covered is about 169.1 meters.

_____

<em>Additional comment</em>

Expressed as a percentage, the slope of this hill is tan(6°) ≈ 10.5%. It would be considered to be a pretty steep hill for driving.

5 0
2 years ago
In Which Quadrant is this true
34kurt

Given:

\sin \theta

\tan \theta

To find:

The quadrant in which \theta lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only \sin\theta and \csc\theta are positive.

In Quadrant III, only \tan\theta and \cot\theta are positive.

In Quadrant IV, only \cos\theta and \sec\theta are positive.

We have,

\sin \theta

\tan \theta

Here, \sin\theta is negative and \tan\theta is also negative. It is possible, if \theta lies in the Quadrant IV.

Therefore, the correct option is D.

5 0
3 years ago
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