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KatRina [158]
3 years ago
7

Find the number of distinct triangles with the measurements a = 5, b =2, and a = 51 degrees.

Mathematics
1 answer:
elixir [45]3 years ago
4 0
The answer is the option b. 1.

Two sides and one angle determine one unique triangle.

If the angle is the between the two sides, you just can use the rule known as SAS, Side Angle Side.

When that is the case you use the cosine rule.

When the known angle is not between the two sides but one of the others, you use sine theorem.

Then in any case when you know two sides and one angle of a triangle the other side and angles are determined, which implies that there is only one possible triangle.
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Which of the following numbers has the correct number of significant digits for the sum of 4.0125 and 5.72?
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2 years ago
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Can someone please help with these 2 word problems ASAP.
PolarNik [594]

Answer:

4.     4.66hours

5.  time_trip = 2.777 h

Step-by-step explanation:

4. A jet plane travels 2 times the speed of a commercial airplane. The distance between Vancouver and Regina is 1730 km. If the flight from Vancouver to Regina on a commercial airplane takes 140 minutes longer than a jet plane, what is the time of a commercial plane ride of this route?

We know that

Speed_commercial = distance/ time_comm

Speed_commercial = 1730 km/ time_comm

Then,

Speed_jet = distance/ time_jet = 2*Speed_commercial

Speed_jet =   1730 km/ time_jet = 2*Speed_commercial

time_comm = 2.333 h + time_jet

1730 km/ time_jet = 2*1730 km/ time_comm

time_comm = 2*time_jet

time_comm = 2*(time_comm  - 2.333h)

time_comm = (2*time_comm  - 4.666h)

time_comm  = 4.666 h

5. A man goes fishing in a river and wants to know how long it will take him to get 10km upstream to his favourite fishing location. The speed of the current is 3 km/hr and it takes his boat twice as long to go 3km upstream as is does to go 4km downstream. How long will it take his boat to get to his fishing spot?

Distance = 10 km upstream

Speed_current = 3 km/h

Upstream

(Speed_boat - Speed_current)  = 3 km / (2*time_downstream)

Downstream

(Speed_boat + Speed_current)  = 4 km / (time_downstream)

We subtract both equations

(Speed_boat + Speed_current) - (Speed_boat - Speed_current) = 4 km / (time_downstream) - 3 km / (2*time_downstream)

2*Speed_current = (5/2 km)/ time_downstream

2*(3 km/h)= (5/2 km)/ time_downstream

time_downstream = 0.416 h

(Speed_boat + 3km/h)  = 4 km / (0.416 h)

Speed_boat  = 6.6 km/h

Trip upstream

(Speed_boat - Speed_current)  = 10 km / (time_trip)

time_trip = 10 km/(3.6 km/h) = 2.777 h

time_trip = 2.777 h

3 0
3 years ago
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