Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
10
Step-by-step explanation:
sqrt root (x2-x1)^2 + (y2-y1)^2
Answer:
Assuming the problem asks to rotate counterclockwise: E' (0,0) F' (0,5) G' (-4,5) H' (-4,0)
If it says rotate clockwise then your points will be: E' (0,0) F' (0,-5) G' (4,-5) H' (4,0)
Step-by-step explanation:
Translate the points first by subtracting 3 from the x-coordinates of each, then subtracting 3 from the y-coordinates of each. Next, to rotate them counterclockwise about the origin 90 degrees, switch the x and y coordinates and the sign of the resulting x-coordinate. To rotate clockwise 90 degrees switch the x and y still but change the sign of the resulting y coordinate.
It is $4.68. You do $58.45 times 0.08, which is $4.676, but you round that to $4.68.
Answer:
28 shirts
Step-by-step explanation:
Let's see what we are given.
there are x amount of shirts ($616 total)
there are 12 in a dozen
the regular shirts are $16
the last 12 shirts are $14
Lets make an equation.
616= 14(12) + 16x
616=168+16x
448=16x
x=28
(Sorry if this explanation is bad)
