<h3>
Answer: 1/2</h3>
The midsegment is always exactly half as long compared to the side it's parallel to.
Put another way, the longer side (4x+20) is twice long as the midsegment (3x).
Answer:
45.1feet
Step-by-step explanation:
Given the following
∠I=90°
∠G=62°, and
GH = 96 feet = Hypotenuse
Required
IG = Adjacent side
Using the SOH CAH TOA identity
Cos theta = Adj/hyp
Cos 62 =IG/96
IG = 96cos62
IG = 96(0.4695)
IG = 45.1feet
Hence the length of IG to the nearest tenth is 45.1feet
Answer:
96 in
Step-by-step explanation:
If the midpoints of the sides are joined to form the smaller triangle, then the perimeter of the smaller triangle is half the perimeter of the greater triangle, because the sides of the smaller triangle are midlines of the greater triangle. By the triangle's midline theorem, each triangle's midline is half the side to which this midline is parallel.
So, if the perimeter of 6th triangle is 3 inches, then the perimeter of 5th triangle is 6 inches, the perimeter of 4th triangle is 12 inches, the perimeter of 3rd triangle is 24 in, the perimeter of 2nd triangle is 48 in and the perimeter of the initial triangle is 96 in
