To see how much interest she'll get after a quarter:
$4132.79 + ($4132.79 × 0.048) = $4331.16
After two quarters:
$4331.16 + ($4331.16 × 0.048) = $4359.06
You can keep going until eventually reaching $8000 then see how many quarters has passed. That's a lot of calculator work!
There's another way that uses less calculation, but more algebra. I call it the exponential formula method! There's this general formula for stuff that increases exponentially, like virus, population, and MONEY:
![m= d {e}^{tc}](https://tex.z-dn.net/?f=m%3D%20d%20%7Be%7D%5E%7Btc%7D)
M is money, d is deposit, t is time taken, and c is just some unknown constant related to the interest rate. There's also the natural logarithm form of this equation, which will come in handy later:
![ln( \frac{m}{d} ) = tc](https://tex.z-dn.net/?f=%20ln%28%20%5Cfrac%7Bm%7D%7Bd%7D%20%29%20%3D%20tc)
Alright first we gotta find that constant c for this equation to be useful! Let's plug in stuff we know.
![ln( \frac{4331.16}{4132.79} ) = (0.25)c](https://tex.z-dn.net/?f=ln%28%20%5Cfrac%7B4331.16%7D%7B4132.79%7D%20%29%20%3D%20%280.25%29c)
We know how much she'll have after one quarter (0.25 years), and we know how much she deposited initially.
After pressing some buttons on the calculator we'll find that c = 0.1875.
Great! Now we can use that formula to find how many years (t) it'll take to reach M=$8000. To save time I'm going to use the natural log form:
![ln( \frac{8000}{4132.79} ) = t(0.1875)](https://tex.z-dn.net/?f=%20ln%28%20%5Cfrac%7B8000%7D%7B4132.79%7D%20%29%20%3D%20t%280.1875%29)
That will give us t = 3.522 which means it'll take approximately 3.5 years for her deposit to reach $8000!