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krek1111 [17]
3 years ago
9

What is the coefficient of the c-term of the algebraic expression 14a - 72r - c - 34d? A) -34

Mathematics
1 answer:
natima [27]3 years ago
8 0
When the coefficient of a term is 1 or -1, we don't write it, we just use the + or - sign. The coefficient of the c term is -1, because of the - sign in front of it and the lack of written coefficient. Any questions?
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Andrea earns $32.25 a day. After 9 days, about how much will she have earned?
Zanzabum

Answer:

290.25 dollars earned

Step-by-step explanation:

32.25 times 9

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3 years ago
Read 2 more answers
-) In a poll, 9 out of 25 students in Lydia's science class say they will vote for her for class president.
V125BC [204]
A) Divide and compare in decimal form -
9/25 = 0.36
4/6=2/7 = 1/4 = 0.25
0.6... > 0.25

B) Fraction to decimal conversion:
4/16 = 2/8 = 1/4 = 0.25

Use long decision or a calculator - 1 divided by four

C) Again, 9/25 = nine divided by twenty-five = 0.36

% Science class)

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Move decimal place to right twice and place “%” at the end.



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4 years ago
If 400 reduced by two times my present age is 296, how old am I now?
vitfil [10]

Answer:

52 years.

Step-by-step explanation:

Represent my current age by c.  Then 400 - 2c = 296, or

104 = 2c

Then c must be 104/2, or 52 years.

4 0
4 years ago
These are the means and standard deviations for samples of prices from two
marysya [2.9K]
Its Letter B!!!!!!!!!!!!
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2 years ago
A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
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