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vivado [14]
3 years ago
9

Laura shades 60 squares on her hundredths grid And Billy shades 50 squares on his hundredths grid. Write the decimal number that

represents by what Laura shaded write the decimal number represented by what billy shaded compare the numbers with either <,>,or=
Mathematics
1 answer:
Andre45 [30]3 years ago
3 0

Answer:

Laura = 0.60

Billy = 0.50

0.60 > 0.50

Step-by-step explanation:

Given

Laura = 60\ shades

Billy = 50\ shades

Required

Represent using decimal number and compare

From the question, we understand that there are 100th grids;

So:

Laura = \frac{60}{100}

Laura = 0.60

Billy = \frac{50}{100}

Billy = 0.50

Comparing both decimals;

Since 0.60 is greater than 0.50, we have:

0.60 > 0.50

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Equivalent expression -(-5.6m-n+9.9
anygoal [31]

Answer:

5.6m + n - 9.9

Step-by-step explanation:

-(-5.6m-n+9.9)

5.6m + n - 9.9

6 0
3 years ago
The length of a rectangle is 8 cm longer than its width. find the dimensions of the rectangle if its area is 108cm
hram777 [196]

Answer:

4+2\sqrt{31}\text{ by } -4+2\sqrt{31}

Or about 15.136 centimeters by 7.136 centimeters.

Step-by-step explanation:

Recall that the area of a rectangle is given by:

\displaystyle A = w\ell

Where <em>w</em> is the width and <em>l</em> is the length.

We are given that the length is 8 centimeters longer than the width. In other words:

\ell = w+8

And we are also given that the total area is 108 square centimeters.

Thus, substitute:

(108)=w(w+8)

Solve for <em>w</em>. Distribute:

w^2+8w=108

Subtract 108 from both sides:

w^2+8w-108=0

Since the equation is not factorable, we can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = 8, and <em>c</em> = -108. Substitute and evaluate:

\displaystyle \begin{aligned} w&= \frac{-(8)\pm\sqrt{(8)^2-4(1)(-108)}}{2(1)} \\ \\ &=\frac{-8\pm\sqrt{496}}{2}\\ \\ &=\frac{-8\pm4\sqrt{31}}{2} \\ \\ &=-4 \pm 2\sqrt{31} \end{aligned}

So, our two solutions are:

w=-4+2\sqrt{31} \approx 7.136 \text{ or } w=-4-2\sqrt{31}\approx -15.136

Since width cannot be negative, we can eliminate the second solution.

And since the length is eight centimeters longer than the width, the length is:

\ell =(-4+2\sqrt{31})+8=4+2\sqrt{31}\approx 15.136

So, the dimensions of the rectangle are about 15.136 cm by 7.136 cm.

5 0
3 years ago
Can somebody help me with this. Will Mark brainliest.
Alex_Xolod [135]

Answer:

2. 60

Step-by-step explanation:

tan x = opp/ adj

tan 40 = x/ 72 ft

x= tan40 * 72 ft

x= 60.415 ft

4 0
3 years ago
Read 2 more answers
What is the sum of square root of -2 and square root of -18
Tasya [4]
Answer is B
4 square root of 2i

7 0
3 years ago
Which pair of ratios does
grandymaker [24]

Answer:

8:14

Step-by-step explanation:

just multiply

5 0
3 years ago
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