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AleksandrR [38]
3 years ago
9

In a lab, a 30% acid solution is being mixed with a 5% acid solution to create a 10% acid solution. What is the ratio of the amo

unt of the 30% solution to the amount of 5% solution used to create the 10% solution? 1:3 1:4 1:5 1:6
Mathematics
2 answers:
tia_tia [17]3 years ago
7 0

Answer:

<em>The ratio of the amount of the 30% solution to the amount of 5% solution will be 1 : 4.</em>

Step-by-step explanation:

Suppose, the amount of 30% acid solution is x and the amount of 5% acid solution is y.

So, the total amount of the mixture = x+y, which is 10% acid solution.

Amount of acid in 30% solution = 30\%\ of\ x=0.30x

Amount of acid in 5% solution =5\%\ of\ y= 0.05y

Amount of acid in the mixture =10\%\ of\ (x+y)=0.10(x+y)

Now, the equation will be......

0.30x+0.05y=0.10(x+y)\\ \\ 0.30x+0.05y=0.10x+0.10y\\ \\ 0.30x-0.10x=0.10y-0.05y\\ \\ 0.20x=0.05y\\ \\ \frac{x}{y} =\frac{0.05}{0.20} =\frac{5}{20}=\frac{1}{4}\\ \\ x:y=1:4

So, the ratio of the amount of the 30% solution to the amount of 5% solution will be 1 : 4.

LuckyWell [14K]3 years ago
4 0

Answer:

  1 : 4

Step-by-step explanation:

Let x represent the amount of 30% solution for 1 unit of 5% solution. Then the amount of acid in the mix is ...

  0.30x + 0.05·1 = 0.10·(x +1)

  0.30x + 0.05 = 0.10x + 0.10 . . . . eliminate parentheses

  0.20x = 0.05 . . . . . . . . . . . . . . . . subtract 0.05+0.10x

  x = 0.05/0.20 = 1/4

That is, the ratio x : 1 is 1 : 4.

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For the considered case, we're given that:

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We identify that the info given on the increasing rate of the circle's radius is 3 \frac{cm}{min} and we identify such as the following differential rate:

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