Please help me with this question

I need help with this!!!!!!!!!!!

GREYUIT [131]

Answer:

D

Step-by-step explanation:

C=2PI R

Radius is 24

pi is 3.14

Then you just solve it which turns out to be 150.8

7 0

2 years ago

Read 2 more answers

What is the equivalent mixed number to 50/7

never [62]

Well the first thing you have to do is find out how many times 7 goes into 50 whole. This is 7. So then you take the answer to (7x7) from 50 which gives you one, and put it over 50. This equals 7 + 1/50

7 0

3 years ago

Read 2 more answers

Suppose I ask you to pick any four cards at random from a deck of 52, without replacement, and bet you one dollar that at least

Tatiana [17]

Answer:

a) No, because you have only 33.8% of chances of winning the bet.

b) No, because you have only 44.7% of chances of winning the bet.

Step-by-step explanation:

a) Of the total amount of cards (n=52 cards) there are 12 face cards (3 face cards: Jack, Queen, or King for everyone of the 4 suits: clubs, diamonds, hearts and spades).

The probabiility of losing this bet is the sum of:

- The probability of having a face card in the first turn

- The probability of having a face card in the second turn, having a non-face card in the first turn.

- The probability of having a face card in the third turn, having a non-face card in the previous turns.

- The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

1) The probability of having a face card in the first turn

In this case, the chances are 12 in 52:

$P_1=P(face\, card)=12/52=0.231$

2) The probability of having a face card in the second turn, having a non-face card in the first turn.

In this case, first we have to get a non-face card (there are 40 in the dech of 52), and then, with the rest of the cards (there are 51 left now), getting a face card:

$P_2=P(non\,face\,card)*P(face\,card)=(40/52)*(12/51)=0.769*0.235=0.181$

3) The probability of having a face card in the third turn, having a non-face card in the first and second turn.

In this case, first we have to get two consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_3=(40/52)*(39/51)*(12/50)\\\\P_3=0.769*0.765*0.240=0.141$

4) The probability of having a face card in the fourth turn, having a non-face card in the previous turns.

In this case, first we have to get three consecutive non-face card, and then, with the rest of the cards, getting a face card:

$P_4=(40/52)*(39/51)*(38/50)*(12/49)\\\\P_4=0.769*0.765*0.76*0.245=0.109$

With these four probabilities we can calculate the probability of losing this bet:

$P=P_1+P_2+P_3+P_4=0.231+0.181+0.141+0.109=0.662$

The probability of losing is 66.2%, which is the same as saying you have (1-0.662)=0.338 or 33.8% of winning chances. Losing is more probable than winning, so you should not take the bet.

b) If the bet involves 3 cards, the only difference with a) is that there is no probability of getting the face card in the fourth turn.

We can calculate the probability of losing as the sum of the first probabilities already calculated:

$P=P_1+P_2+P_3=0.231+0.181+0.141=0.553$

There is 55.3% of losing (or 44.7% of winning), so it is still not convenient to bet.

5 0

3 years ago

GEOMETRY. 20 POINTS. PLEASE DO NOT GIVE STUPID ANSWERS.

sp2606 [1]

Hey there!

A quadrilateral has 360 degrees. So add all the degrees together to 360. 9x+1+5x-12+8x+61+90=360. 90 degrees is in the bottom left corner. Combine like terms. 22x+140=360. Subtract 140 from each side. 22x=220. Divide 22 on each side to get x=10. Plug in 10 for x in angle D. 5(10)-12=38. The measure of angle D is 38 degrees.

I hope this helps!

3 0

3 years ago

Line segment BA is tangent to the circle. A circle is shown. Secant D B and tangent B A intersect at point B outside of the circ

Mama L [17]

Answer: 88 units

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers