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3 years ago

Can anyone help me with these two problems? I found the distance to one. Please, assignment is due tonight. Thank you.

Mathematics

2 answers:

kow [346]3 years ago

7 0

I hope this helps you I am 85% sure this is correct

klasskru [66]3 years ago

6 0

Answer:

32 mi @ N77°E

Step-by-step explanation:

The route of travel forms legs of a right triangle, so the final distance (d) from harbor can be found using the Pythagorean theorem:

d² = 28² +16² = 784 +256 = 1040

d = √1040 ≈ 32.249 . . . miles

___

The angle (α) added to the original N47°E bearing can be found using the fact that opposite and adjacent sides are given. So, they can tell you the tangent of the angle:

tan(α) = 16/28

α = arctan(16/28) ≈ 29.74°

Then the bearing to the final position is ...

47° +29.74° = 76.74° . . . . . east of north

Rounded to whole numbers, the final position from harbor is ...

32 miles @ N 77° E

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4 years ago

Read 2 more answers

PLEASE SHOW WORK

CaHeK987 [17]

(C)

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$V = \dfrac{\pi}{3}r^2h$

Taking the derivative of V with respect to time, we get

$\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)$

$\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)$

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3 years ago

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