Answer:
for all x in the domain of f(x), or odd if, f(−x) = −x, for all x in the domain of f(x), or neither even nor odd if neither of the above are true statements. A kth degree polynomial, p(x), is said to have even degree if k is an even number and odd degree if k is an odd number
Step-by-step explanation:
Answer:
Parallel
Step-by-step explanation:
These 2 lines are parallel because they have the same slope (7).
Answer: An equality is a statement of equal measure. It stands for an absolute statement, without any leeway. That is, there is only a set number of solutions they can take.
Here is an example: x + 17 = 20
In this case, x can only take one solution because it is an absolute statement. Obviously, these can change, but conceptually, they will contain a set of answers a variable can take.
An equality with degree of n will inevitably have n number of answers a variable can take.
However, there are more solutions x can take for an equality. This is because inequality signs are a broader set of equality signs.
Example: x + 17 > 20
In the previous example, there was only one solution that x can take, namely x = 3. However, if we have an inequality, we're merely finding all sets of values x can take that will keep this statement true. In this case, there are an infinite amount of solutions, provided x is greater than 3.
Properties of inequalities vs equalities
This segment is quite tricky to grasp, because we are so used to the equality. The hardest section is to determine when to change the inequality sign. Whenever we multiply or divide by a negative number, we must flip the sign.
Answer:
4b. −6x + y = −4
4a. 7x + 4y = −12
3b. y = ½x + 3
3a. y = −6x + 5
2b. y + 2 = −⅔(x + 3)
2a. y - 3 = ⅘(x - 5)
1b. y = -x + 5
1a. y = 5x - 3
Step-by-step explanation:
4.
Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:
b.
2 = 6[1] + b
6
−4 = b
y = 6x - 4
-6x - 6x
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−6x + y = −4 >> Standard Equation
a.
4 = −7⁄4[-4] + b
7
−3 = b
y = −7⁄4x - 3
+7⁄4x +7⁄4x
____________
7⁄4x + y = −3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]
4[7⁄4x + y = −3]
7x + 4y = −12 >> Standard Equation
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3.
Plug both coordinates into the Slope-Intercept Formula:
b.
5 = ½[4] + b
2
3 = b
y = ½x + 3 >> EXACT SAME EQUATION
a.
−1 = −6[1] + b
−6
5 = b
y = −6x + 5
* Parallel lines have SIMILAR <em>RATE OF CHANGES</em> [<em>SLOPES</em>].
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2.
b. y + 2 = −⅔(x + 3)
a. y - 3 = ⅘(x - 5)
According to the <em>Point-Slope Formula</em>, <em>y - y₁ = m(x - x₁)</em>, all the negative symbols give the OPPOSITE TERMS OF WHAT THEY REALLY ARE, so be EXTREMELY CAREFUL inserting the coordinates into the formula with their CORRECT SIGNS.
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1.
b. y = -x + 5
a. y = 5x - 3
Just write out the Slope-Intercept Formula as it is given to you.
I am joyous to assist you anytime.
For each term you will plug in the term number into n. 2, 4, 8, 16
