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elena55 [62]
4 years ago
13

Find the volume of a box that will hold nine 9.425 cm3 cylindrical containers that each measure 3 centimeters long. (round to ne

arest whole number)
Mathematics
1 answer:
kipiarov [429]4 years ago
6 0
To find the volume of a box that would hold these nine cylinders, you would start with the formula for volume of a cylinder. V=pi x r^2 x h. Substitute in the known volume and the known Height. 9.425=pi x r^2 x 3. Divide both sides by three to get approximately 3.143 = pi x r^2. Divided by pi on both sides. This leaves you with one = r^2. So the radius is equal to one. If the radius equals one, the diameter is two. Assuming the cylinders are arranged in a 3 x 3 array, the length and width of the rectangle or box would be 6cm x 6cm. To find the volume of the box necessary, multiply the length of six by the width of six by the height of three. The volume would be 108 square cm.
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Answer:

d = m + 10\\d+m=150

Step-by-step explanation:

If Avery wants the amount of dark chocolate (d) to be 10 kg higher than the amount of milk chocolate (m), then the following relationship must be true:

d = m + 10

If the total amount of chocolate must equal 150 kg, then:

d+m=150

The system of equations that represent this situation is:

d = m + 10\\d+m=150

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Use Multiplication Distribute Property: (xy)^a = x^ay^a

6^2(x^-2)^2(0.5x)^4

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36(x^-2)^2(0.5x)^4

Use this rule: (x^a)^b = x^ab

36x^-4(0.5x)^4

Use the Negative Power Rule: x^-a = 1/x^a

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