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3 years ago

What is the value of y in the equation 2 + y = −3? -1 -5 1 5

Mathematics

1 answer:

Thepotemich [5.8K]3 years ago

7 0

To do this subtract 2 from each side of the equation to get y = -5, so the value of y in this is -5. Hope this helps!

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Y = 4x + 50

y is height, 4 meters per second (x), 50m initial height

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3 years ago

-8.5n = 17<br> pls help me

erastova [34]

I believe the answer is n= -2

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3 years ago

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evablogger [386]

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3 years ago

Seven students in class A and ten students in class B ate pizza. There are 25 students in class A and 30 students in class B. Wh

Pavlova-9 [17]

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2 years ago

What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.

Anit [1.1K]

The equation of the line is, $\rm y = 3x + 1$ .

Given that,

The equation of the line is,

$\rm y = \dfrac{1}{3} x+4\\$

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

$\rm = \dfrac{1}{3}x + 4\\$

On comparing with the standard equation of the line y = mx +c.

The slope of the line $m_1$ is 1/3.

When two lines are perpendicular the relation between these slopes is,

$\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3$

And line contains the point (-2, -5).

Then,

$\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1$

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

$\rm y = mx +c \\\\y = 3x +1$

Hence, The required equation of the line is, $\rm y = 3x + 1$ .

For more details refer to the link given below.

brainly.com/question/14388443

7 0

3 years ago