What is the common ratio for the sequence 1, 4, 16, 64,...? 2 4

Mathematics

2 answers:

tatyana61 [14]3 years ago

5 0

The answer would be four

PIT_PIT [208]3 years ago

4 0

The given equation is a geometric sequence.
It has a common ratio. You can get it by dividing the number in the sequence by the number before it.

Just like r= 16/4= 4

You might be interested in

Does 10,15,20 form a right triangle

sveta [45]

A right triangle can only be formed when you use the 3/4/5 rule.
The 3/4/5 rule is a^2 + b^2 = c^2.

We will use 10 for a, 15 for b, and 20 for c.

a^2 + b^2 = c^2

Plug in 10 for a, 15 for b, and 20 for c.

10^2 + 15^2 = 20^2

10^2 = 100

15^2 = 225

20^2 = 400

100 + 225 = 400
This is not applicable, as 100 + 225 = 325.

Your answer is:

No, 10,15,20 does not form a right triangle.

I hope this helps!

5 0

3 years ago

each day ashley practices free throws. the first day she takes 12 shots and every day after she takes 2 more than the previous d

morpeh [17]

I added 12+5(2) and got 22. Since 12 was how many shots she made on the first day and she makes 2 more shots than the previous day I did 5x2 which is 10 and add them up it makes 22:)

8 0

3 years ago

The sum of two numbers is 24 and their difference is 2. What are the numbers?

Musya8 [376]

Its 4 and 6
4 X 6= 24
6-4= 2

8 0

3 years ago

Read 2 more answers

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p

Artemon [7]

Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that $X = 80, \mu = 77, \sigma = 4.9$