Around 90% of the time, you'll get joke answers or answers from bots. Even if I report their answers, they will report my question back? Even though their answers are completely irrelevant to my questions? Also, your moderators are probably 12 years olds, because why? THEY. DELETE. EVERY. CORRECT. ANSWER. I. MADE. Not to mention, that there are a bunch of other users that started grouping and bullied me with vulgar words. Disgusting. Is this what your moderating has become, Huh? Brainly? IS THIS WHAT YOU CALL A PEACEFUL FRIENDLY WEBSITE FOR EVERYONE? Shame on you, I will not use this website again, until you fix your moderation "ENTIRELY".
Answer:
0.75
Step-by-step explanation:
Given,
P(A) = 0.6, P(B) = 0.4, P(C) = 0.2,
P(A ∩ B) = 0.3, P(A ∩ C) = 0.12, P(B ∩ C) = 0.1 and P(A ∩ B ∩ C) = 0.07,
Where,
A = event that the selected student has a Visa card,
B = event that the selected student has a MasterCard,
C = event that the selected student has an American Express card,
We know that,
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.12 - 0.1 + 0.07
= 0.75
Hence, the probability that the selected student has at least one of the three types of cards is 0.75.
.0099 is the only positive number above zero and would have the highest value
Answer:
Step-by-step explanation:
n could be : -14, -13, -12... -1, 0 , 1, 2, 3 ,4,5
First, you must know these formula d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx
(secx)dy/dx=e^(y+sinx), implies <span>dy/dx=cosx .e^(y+sinx), and then
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
