Answer:
(-1, -2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-2x + y = 0
5x + 3y = -11
<u>Step 2: Rewrite Systems</u>
-2x + y = 0
- Add 2x on both sides: y = 2x
<u>Step 3: Redefine Systems</u>
y = 2x
5x + 3y = -11
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 5x + 3(2x) = -11
- Multiply: 5x + 6x = -11
- Combine like terms: 11x = -11
- Isolate <em>x</em>: x = -1
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: y = 2x
- Substitute in <em>x</em>: y = 2(-1)
- Multiply: y = -2
<u>Step 6: Graph Systems</u>
<em>Check the solution set.</em>
Answer:
{x,y,z}={5,−3,3}
Step-by-step explanation:
[1] 2x + 4y + z = 1
[2] x - 2y - 3z = 2
[3] x + y - z = -1
// Solve equation [3] for the variable y
[3] y = -x + z - 1
// Plug this in for variable y in equation [1]
[1] 2x + 4•(-x +z -1) + z = 1
[1] -2x + 5z = 5
// Plug this in for variable y in equation [2]
[2] x - 2•(-x +z -1) - 3z = 2
[2] 3x - 5z = 0
// Solve equation [2] for the variable x
[2] 3x = 5z
[2] x = 5z/3
// Plug this in for variable x in equation [1]
[1] -2•(5z/3) + 5z = 5
[1] 5z/3 = 5
[1] 5z = 15
// Solve equation [1] for the variable z
[1] 5z = 15
[1] z = 3
// By now we know this much :
x = 5z/3
y = -x+z-1
z = 3
// Use the z value to solve for x
x = (5/3)(3) = 5
// Use the x and z values to solve for y
y = -(5)+(3)-1 = -3
Solution :
{x,y,z} = {5,-3,3}
Answer:
n = 5
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
Answer:
Assuming that Andrew made the trip in one day, the cost of the truck rental is $89
Step-by-step explanation:
You can find the answer essentially by plugging in 78 for every variable m: C(78)=0.50(78)+50
C(78)=39+50
C(78)=89
The cost of driving 78 miles in one day is $89.
