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3 years ago

Explain what is meant by a compound. Give an example. How do compounds form?

Biology

1 answer:

MaRussiya [10]3 years ago

6 0

Answer:

the two or more things that combined together is called compound.

Explanation:

example:

when the element NA and CL combine together form compound NACL.

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(ASAP PLEASE) Dichotomous key of brewer’s yeast (saccharomyces cerevisiae) e. coli bacteria (escherichia coli) green hydra (hydr

Serjik [45]

Answer:

Does the organism have legs?

Does the organism reproduce asexually?

Can the organism ferment?

Is the organism infectious?

Explanation:

The questions HAVE to be yes or no, in order for it to effectively determine which species is which.

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3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

In an experiment to test a new drug’s effectiveness, one group is given a larger dosage than is typically prescribed, and a seco

Tom [10]

One group is given a larger dosage than is typically prescribed.
A second group is given a smaller dosage than is typically prescribed
Then results of the groups are compared to each other.

The thing that is missing in this experimental design is a third group who are tested with the typical dosage.

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3 years ago

A couple is having a baby.The father is homozygous dominant (HH) for curly hair. The mother is homozygous recessive (hh) for str

Alona [7]

Answer:

Your question is incomplete but supposing that the mother is a recessive allele and the father is dominant, we deduce that his daughter could have curly hair or else wavy hair that would be a combination of the two since both parents can incompletely dominate

Explanation:

The chances that your child has curly hair is 50%, that is, it would be the most likely, and also the genotype that you would need for this child to have curly hair would be: CC with CS or CC with CC

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3 years ago

The term pseudoscience refers to evidence that _____.

Nataliya [291]

The prefix pseudo means "not genuine", or fake.
So your answer is: C. Pretends to be scientific, but actually is not.

6 0

3 years ago