Answer:
The answer is y=1/3x-1
Step-by-step explanation:
m=1/3
y-y=m(x-x1)
y-(-1)=1/3(x-0)
y+1=1/3x-0
-1 -1
y=1/3x-1
So, the subtraction looks like this:
223
-119
_______
The reason why combining place values here is necessary is that 3 is less than 9 (so I can't just substract in the one's place without going to negative numbers)
so we combine the ones and tens places and substract the whole: 23-19 is four!
223
-119
_______
04
and then we continue
223
-119
_______
204
and that's the result!
Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
The answer to this is oh nvm
B the answer is B - hope this helps you out