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son4ous [18]
3 years ago
15

Could I solve this inequality by completing the square? How would I do so?

Mathematics
1 answer:
sammy [17]3 years ago
8 0

Answer:

\large\boxed{x>-2+\sqrt{14}\ \vee\ x

Step-by-step explanation:

x^2+4x>10\\\\x^2+2(x)(2)>10\qquad\text{add}\ 2^2=4\ \text{to both sides}\\\\x^2+2(x)(2)+2^2>10+4\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(x+2)^2>14\Rightarrow x+2>\sqrt{14}\ \vee\ x+2-2+\sqrt{14}\ \vee\ x

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Given the function f(x) = 4(x+3) − 5, solve for the inverse function when x = 3.
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Hello,

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f^(-1)(x)=(x-7)/4
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Write an equivalent expression for 7 + 5 k minus 2 minus 3 k + n. Which statements are true about the steps for writing the equi
Nataly [62]

Answer:

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2 years ago
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Papessa [141]

Answer:

discriminant =0

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Step-by-step explanation:

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when the equation is written in the form  ax^2 +bx+c

f(x) = 3x^2 +24x+48

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discriminant = 24^2 - 4(3)*(48)

                      =576-576

                        =0


If the discriminant >0  we have 2 real roots

if discriminant = 0  we have 1 real root

if discriminant <0 we have 2 complex roots

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Read 2 more answers
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