ax²+bx+c=0
4a²x²+4abx+4ac=0
4a²x²+4abx=-4ac
4a²x²+4abx+b²=b²-4ac
(2ax+b)²=b²-4ac
Answer:
Option D is correct.
The equation with roots 3 plus or minus square root 2 is x² - 6x + 7
Step-by-step explanation:
The roots of the unknown equation are
3 ± √2, that is, (3 + √2) and (3 - √2)
The equation can then be reconstructed by writing these roots as the solutions of the quadratic equation
x = (3 + √2) or x = (3 - √2)
The equation is this
[x - (3 + √2)] × [x - (3 - √2)]
(x - 3 - √2) × (x - 3 + √2)
x(x - 3 + √2) - 3(x - 3 + √2) - √2(x - 3 + √2)
= x² - 3x + x√2 - 3x + 9 - 3√2 - x√2 + 3√2 - 2
Collecting like terms
= x² - 3x - 3x + x√2 - x√2 - 3√2 + 3√2 + 9 - 2
= x² - 6x + 7
Hope this Helps!!!
The Four basic Mathematical Operations are:
•Addition
•Subtraction
•Multiplication
•Division
Answer and Step-by-step explanation:
Twelve times four squared.
This is how you would write the expression in word format.
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