Question

I'll give brainliest to whoever shows their work. Plz answer fast.

Answer 1

Answer:

The Correct Would Be OPTION : D

Step-by-step explanation:

Answer 2

Lets check the validity of each one of our statements:

Statement A is false. The square root of a number less than 1 is greater than the number itself. In fact, $\sqrt{ \frac{4}{5} } = \sqrt{0.8} =0.89$. Since $0.89$ is greater than $0.8$, $\sqrt{0.8}$ is greater than $\frac{4}{5}$; therefore, statement A is false.

Statement B is false. The square root of a number greater than 1 is less than the number itself. in fact, $\sqrt{7} =2.64$, whereas $\sqrt{7^2} =7$. Since 2.64 is less than 7, $\sqrt{7}$ is less than $\sqrt{7^2}$; therefore statement B is false.

Statement C is false. $\sqrt{7}$ is actually less than 7 divided by two, so there is no way that $\sqrt{7}$ is between 6 and 8. In fact $\sqrt{7} =2.64$. Since 5 is greater than 2.64, $( \sqrt{5} )^2$ is greater than $\sqrt{7}$; therefore, statement C is false.

Statement D is true. $\sqrt{7} =2.64$. Since 2.64 is greater than 0.8, $\sqrt{7}$ is greater than $\frac{4}{5}$.

We can conclude that Jana should use statement D to create her list; also the correct order from least to greatest is: $\frac{4}{5}$, $\sqrt{0.8}$,$\sqrt{7}$, $( \sqrt{5} )^2$, $\sqrt{7^2}$