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noname [10]
3 years ago
13

Really need help with this, thank you!!!!!

Mathematics
1 answer:
KengaRu [80]3 years ago
4 0
Here your answer for your question

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The first term in a sequence is -2 and the common ratio is 3. What is the sixth term of the sequence?
AlekseyPX
It's the Geometric Sequence.

The n<span>-th term of a geometric sequence with initial value </span>a<span> and common ratio </span>r<span> is given by:
</span>
a_n=a_1\cdot r^{n-1}\ for\ n\in\mathbb{N^+}

We have:

a_1=-2;\ r=3;\ n=6

Substitute:

a_6=-2\cdot3^{6-1}=-2\cdot3^5=-2\cdot243=-486

Answer: The sixth term is equal -486.
7 0
4 years ago
What are the solutions of the equation x4 95x2 â€"" 500 = 0? Use factoring to solve.
liq [111]

All the values of the <em>x</em> <em> </em>for the given function are \sqrt{5},-\sqrt{5}, 10i and -10i.

Given-

Given function is,

x^{4}+95x^2-500=0

Rewrite the equation,

(x^2)^2+95x^2-500=0

Let <em>u </em>in place of x^2 and rewrite the equation in the form of u,

u^2+95u-500=0

Break the 95 in factors and rewrite the equation,

u^2+100u-5u-500=0

u(u+100)-5(u+100)=0

(u+100)(u-5)=0

Replace the value of u with x^2,

(x^2+100)(x^2-5)=0

It is known that If any individual factor on the left side of the equation is equal to zero then the entire expression will be equal to zero. therefore we get,

x^2-5=0

further, solve it,

x^2=5

x=\sqrt{5},-\sqrt{5}

And another factor is

x^2+100=0

x^2=-100

x=10i,-10i

Hence, all the values of the <em>x </em>for the given function are \sqrt{5},-\sqrt{5},  10i , and  -10i.

For more about the factorization, follow the link below-

brainly.com/question/6810544

5 0
3 years ago
Jon and Becky measured the circle-shaped part of a sun they drew on the sidewalk.
lisov135 [29]
The approximate area of the circle is A
7 0
3 years ago
What is the factored form of this expression?
lawyer [7]

Answer:  The answer is D (4). The expression cannot be factored.

4 0
3 years ago
I need to solve for x using the pythagorean theorem some how (I think) please only answer if you can give a hint or the answer w
borishaifa [10]

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{\stackrel{3959+5.9}{3964.9}}\\ a=\stackrel{adjacent}{3959}\\ b=\stackrel{opposite}{x}\\ \end{cases} \\\\\\ \sqrt{3964.9^2-3959^2}=x\implies \sqrt{46751.01}=x\implies 216.22\approx x

4 0
3 years ago
Read 2 more answers
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