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olga2289 [7]
3 years ago
8

Find a so that the point (1,2) is on the graph of f (x)=ax^2+5

Mathematics
1 answer:
12345 [234]3 years ago
3 0
Answer: a = -5
Heyy, so with this question you would have to substiute 1 for x because normally the coordinates have x first then y. E.g. (x,y)

soo, f(1) = a(1)^2 +5
then, f(1) = a + 5
then equate to zero. E.g. a+5=0
then move over 5 to other side E.g. a=-5
soo.. yah.. pretty sure haha :)
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The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

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<u>Equivalent algebraic expressions</u> are those expressions which on simplification give the same resulting expression.

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